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发表时间:2014-10-19
/** * Find Minimum in Rotated Sorted Array * * <pre> * Suppose a sorted array is rotated at some pivot unknown to you * beforehand. * * (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). * * Find the minimum element. * * You may assume no duplicate exists in the array. * </pre> * */ public class FindMinimuminRotatedSortedArray { public class Solution { public int findMin(int[] num) { return _findMin(num, 0, num.length - 1); } private int _findMin(int[] num, int start, int end) { if (num[start] < num[end]) { return num[start]; } if (start == end) { return num[end]; } if (start + 1 == end) { return num[end]; } int mid = (end + start) / 2; if (num[mid] < num[start]) { return _findMin(num, start, mid); } else { return _findMin(num, mid, end); } } } } 声明:ITeye文章版权属于作者,受法律保护。没有作者书面许可不得转载。
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