请教Spring注入得到的值为null

0 0

请教Spring注入得到的值为null15

大家好，我在搭建ssh2框架时，spring注入值为null，代码如下。

1 applicationContext.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd">

<bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource">
<property name="driverClassName" value="com.mysql.jdbc.Driver">
</property>
<property name="url" value="jdbc:mysql://localhost:3306/test8">
</property>
<property name="username" value="root"></property>
<property name="password" value="root"></property>
</bean>
<bean id="sessionFactory"
class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
<property name="dataSource">
<ref bean="dataSource" />
</property>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">
org.hibernate.dialect.MySQLDialect
</prop>
</props>
</property>
</bean>


<bean id="hibernateTemplate" class="org.springframework.orm.hibernate3.HibernateTemplate">
<property name="sessionFactory">
<ref bean="sessionFactory"/>
</property>
</bean>


<bean id="userDAO" class="com.test.dao.UserDaoImpl">
<property name="hibernateTemplate">
<ref bean="hibernateTemplate"/>
</property>
</bean>


<bean id="userService" class="com.test.service.UserServiceImpl">

<property name="userDao" ref="userDAO"></property>
</bean>

<bean id="userAction" class="com.test.action.UserAction" scope="prototype">
<property name="userServiceImpl" ref="userService"></property>
</bean>
</beans>

2 web.xml

<?xml version="1.0" encoding="UTF-8"?>

<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"

xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"

xsi:schemaLocation="http://java.sun.com/xml/ns/javaee

http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

<filter-name>struts2</filter-name>

<filter-class>

org.apache.struts2.dispatcher.FilterDispatcher

</filter-class>

</filter>

<filter-mapping>

<filter-name>struts2</filter-name>

<url-pattern>/*</url-pattern>

</filter-mapping>

<listener-class>

org.springframework.web.context.ContextLoaderListener

</listener-class>

</listener>

</web-app>

3 struts.xml

<?xml version="1.0" encoding="UTF-8" ?>

<!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.1//EN" "http://struts.apache.org/dtds/struts-2.1.dtd">

<result name="success">/showAll.jsp</result>

</action>

</package>

</struts>

4 action类如下

package com.test.action;

import javax.servlet.http.HttpServletRequest;

import javax.servlet.http.HttpServletResponse;

import org.apache.struts2.interceptor.ServletRequestAware;

import org.apache.struts2.interceptor.ServletResponseAware;

import com.opensymphony.xwork2.ActionSupport;

import com.test.bean.User;

import com.test.service.UserService;

public class UserAction extends ActionSupport implements ServletRequestAware,

ServletResponseAware{

/**

private static final long serialVersionUID = -1885854904242552572L;

HttpServletRequest request;

HttpServletResponse response;

private UserService userServiceImpl;

/**

* @param userServiceImpl the userServiceImpl to set

public void setUserServiceImpl(UserService userServiceImpl) {

this.userServiceImpl = userServiceImpl;

}

/**

* @return the userServiceImpl

public UserService getUserServiceImpl() {

return userServiceImpl;

}

public String addUser1() {

System.out.println("AAAA");

this.response.setContentType("text/json;charset=utf-8");

this.response.setCharacterEncoding("UTF-8");

User user = new User();

user.setUsername("admin");

user.setPassword("admin");

user.setDeviceId("aaa");

boolean flag = userServiceImpl.addUser(user);//这里userServiceImpl值为null

if(flag){

return SUCCESS;

}else{

return ERROR;

}

@Override

public void setServletResponse(HttpServletResponse arg0) {

// TODO Auto-generated method stub

this.response = arg0;

}

@Override

public void setServletRequest(HttpServletRequest arg0) {

// TODO Auto-generated method stub

this.request = arg0;

}

请教。

2014年1月14日 09:47

eoeyedroid
3
0 0 4

3个答案按时间排序按投票排序

0 0

你可以产尝试一下：在addUser1()方法中声明
BeanFactory factory = new ClassPathXmlApplicationContext("你的Spring配置文件");
?? action = (??) factory.getBean("你的beanaction");
??.userServiceImpl.addUser(user);

2014年1月23日 13:53

youngliu_liu
0
0 0 2

添加评论

0 0

从你的配置信息看出你有UserService的接口实现类那么
定义的userservice 的变量 userServiceImpl 和你UserService实现接口类<bean id="userService" class="com.test.service.UserServiceImpl>命名冲突
你要么命名 private UserService userService 生成get set方法
userSercvice.addUser（）再看看

如果你没有定义UserService的接口，直接是类方法调用哪就是上面仁兄说的那样定义

2014年1月15日 09:39