ajax查询怎么写不要用prototype、jquery 纯JS的哈

0 0

ajax查询怎么写不要用prototype、jquery 纯JS的哈0

<form action="http://118.122.89.217:8808/ANBOSS/productView.c?do=queryProduct" method="post">
条码:<input name="barCode"/>
<input type="submit">
</form>

问题补充：希望能把我提供的表单完整的写一下html哈谢谢！

Ajax

2012年12月13日 11:51

028wz
0
0 0 5

4个答案按时间排序按投票排序

1 0

采纳的答案

<%@ page language="java" contentType="text/html; charset=UTF-8"
    pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Insert title here</title>
</head>
<body>
<script type="text/javascript" language="javascript"> 
   window.onload = function() {
      var request = null; 
      document.getElementById("form").onsubmit = function() {
         //可以显示正在查询的图片   
         
         try {
           request = new XMLHttpRequest();
         } catch (trymicrosoft) {
           try {
             request = new ActiveXObject("Msxml2.XMLHTTP");
           } catch (othermicrosoft) {
             try {
               request = new ActiveXObject("Microsoft.XMLHTTP");
             } catch (failed) {
               request = false;
             }   
           }
         }
         var url = this.action + "&barCode=" + escape(document.getElementById("barCode").value);
         request.open("GET", url, true);
         request.onreadystatechange = callback;
         request.send(null);
         
         return false;
      };
      
      function callback() {
          if (request.readyState == 4) {
              if (request.status == 200) {
                 //处理返回的内容
                 alert(request.responseText);
              }
          }
      }
   
   };
</script> 
</head> 
<body> 
<form id="form" action="http://118.122.89.217:8808/ANBOSS/productView.c?do=queryProduct" method="post">
条码:<input id="barCode" name="barCode"/>
<input type="submit">
</form>
</body>
</html>

2012年12月13日 12:04

jinnianshilongnian
7280
2 3 591

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1 0

    var xmlhttp;
        function ajax(){
            if(window.ActiveXObject){
                xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
            }else if(window.XMLHttpRequest){
                xmlhttp = new XMLHttpRequest();
            }
            var url = "自定义";
            xmlhttp.open("GET",url,true);
            xmlhttp.onreadystatechange = openURL;
            xmlhttp.send(null);
        }

        function openURL(){
            if (xmlhttp.readyState == 4){
                if (xmlhttp.status == 200){
                    var json = xmlhttp.responseText;//返回的结果
                    window.open(json.authorizeUrl);
                }
            }
        }

2012年12月13日 11:56