求一个关于字符串切分的正则

0 0

求一个关于字符串切分的正则0

现在有一个形如下面的形式的字符串：'2012-06-20 00:00:00,017', 'INFO', 'quartzScheduler_Worker-10' 要用正则提取出单引号内的字符串 (第一个引号里面有逗号)，则提取出的结果有如下三部分为：2012-06-20 00:00:00,017 INFO quartzScheduler_Worker-10 希望好心人帮下先谢了

java 正则字符串

2012年8月07日 08:26

tengyue5i5j
0
0 0 2

String str="'2012-06-20 00:00:00,017', 'INFO', 'quartzScheduler_Worker-10'";
String regex = "('.*?')+?";

Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(str);
boolean found = false;
while (matcher.find())
{
System.out.printf(
"I found the text \"%s\" starting at index %d and ending at index %d.%n",
matcher.group(), matcher.start(), matcher.end());
found = true;
}
if (!found)
{
System.out.printf("No match found.%n");
}

2012年8月09日 16:32

fangfumin
14
0 1 12

2条评论

0 0


	String s = "'2012-06-20 00:00:00,017', 'INFO', 'quartzScheduler_Worker-10'";
	Matcher matcher = Pattern.compile("'.*?'").matcher(s);
	while(matcher.find()) {
	    String text = matcher.group();
	    System.out.println(text.substring(1, text.length()-1));

2012年8月08日 12:23

sy197661944
2
0 0 4

3条评论

0 0

java对正则的支持比JS强很多，但发现很多写Java的人似乎不屑于学习正则

package self.saturday;

import java.util.ArrayList;
import java.util.List;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class TestRegExp {
	public static void main(String[] args) {
		String str = "'2012-06-20 00:00:00,017','INFO','quartzScheduler_Worker-10'";
		Pattern pattern = Pattern.compile("'([^']+)'");
		Matcher matcher = pattern.matcher(str);
		List<String> list = new ArrayList<String>();
		
		while (matcher.find()) {
			list.add(matcher.group(1));
		}
		
		System.out.println(joinList(list));
	}
	
	public static String joinList(List<String> list){
		return joinList(list, "\n");
	}
	
	public static String joinList(List<String> list, String separator){
		if(list == null || list.size() == 0){
			return "";
		}
		
		StringBuffer buff = new StringBuffer();
		
		buff.append(list.get(0));
		for(int i=1, len=list.size(); i<len; i++){
			buff.append(separator + list.get(i));
		}
		
		return buff.toString();
	}
}

2012年8月08日 09:57

xingqiliudehuanghun
42
0 0 0

2条评论

0 0

String str = "'2012-06-20 00:00:00,017', 'INFO', 'quartzScheduler_Worker-10'";
Pattern pattern = Pattern.compile("'(.*?)'");
Matcher matcher = pattern.matcher(str);
while (matcher.find()) {
	System.out.println(matcher.group(1));
}

2012年8月07日 17:02

su1216
38
0 0 6

2条评论

0 0

追加一个正则简单的。

       String str ="'2012-06-20 00:00:00,017','INFO','quartzScheduler_Worker-10'";
        Pattern p = Pattern.compile("'([\\s0-9:,-]+)','(\\w+)','(\\S+)'");
        Matcher matcher = p.matcher(str);
        while (matcher.find()) {
                System.out.println(matcher.group(1)+matcher.group(2)+matcher.group(3));
    }

2012年8月07日 15:51

green_tea
48
0 0 3

添加评论

0 0

  Pattern p = Pattern.compile("'(\\d{4}-\\d{2}-\\d{2}\\s?\\d{2}:\\d{2}:\\d{2},\\d{3})','(\\w+)','(\\S+)'");
        Matcher matcher = p.matcher(str);
        while (matcher.find()) {
                System.out.println(matcher.group(1)+matcher.group(2)+matcher.group(3));
        }

2012年8月07日 15:09

green_tea
48
0 0 3

添加评论

0 0

这个遍历两次才能处理好。

2012年8月07日 13:54

jiaxiaodong999
30
0 0 0

添加评论

0 0

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class RegexDemo {
	public static void main(String[] args) {
		String str = "'2012-06-20 00:00:00,017','INFO','quartzScheduler_Worker-10'";
		Pattern pattern = Pattern.compile("([^'])+");
		//
		Matcher matcher = pattern.matcher(str);
		while (matcher.find()) {
			if (!matcher.group().equals(","))
				System.out.println(matcher.group());
		}
	}
}

或者

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class RegexDemo {
	public static void main(String[] args) {
		String str = "'2012-06-20 00:00:00,017','INFO','quartzScheduler_Worker-10'";
		Pattern pattern = Pattern.compile("'([^'])+'");
		//
		Matcher matcher = pattern.matcher(str);
		while (matcher.find()) {
				System.out.println(matcher.group().replace("'", ""));
		}
	}
}

2012年8月07日 10:24