OpenJPA问题！请教...

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OpenJPA问题！请教...5

JPA配置文件：
XML code
<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/persistence
    http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0">

    <persistence-unit name="JPATestPU" transaction-type="RESOURCE_LOCAL">
        <provider>org.apache.openjpa.persistence.PersistenceProviderImpl</provider>
          <properties>
            <property name = "openjpa.ConnectionDriverName" value = "com.mysql.jdbc.Driver"/>
            <property name = "openjpa.ConnectionURL" value = "jdbc:mysql://localhost:3306/test"/>
            <property name = "openjpa.ConnectionUserName" value = "root"/>
            <property name = "openjpa.ConnectionPassword" value = "root"/>
          </properties>
    </persistence-unit>

</persistence>

Java Main 方法：

Java code
package dao;

import java.util.List;

import javax.persistence.EntityManager;
import javax.persistence.EntityManagerFactory;
import javax.persistence.Persistence;

import entity.News;

public class Test {

    /**
     * @param args
     */
    public static void main(String[] args) {
        EntityManagerFactory emf=Persistence.createEntityManagerFactory("JPATestPU");
        EntityManager em= emf.createEntityManager();
        News news=new News();
        news.setId(1);
        news.setUsername("aaaaaaaa");
        news.setContent("bbbbbbb");
        news.setIp("127.0.0.1");
        news.setType(1);
        news.setUsername("aaaaaaaaaaa");
        news.setXianshi(1);

        em.persist(news);

        System.out.println("success");
    }

}

异常信息：
HTML code
282 JPATestPU INFO   [main] openjpa.Runtime - Starting OpenJPA 1.2.0
563 JPATestPU INFO   [main] openjpa.jdbc.JDBC - Using dictionary class "org.apache.openjpa.jdbc.sql.MySQLDictionary".
Exception in thread "main" <openjpa-1.2.0-r422266:683325 nonfatal user error> org.apache.openjpa.persistence.ArgumentException: Attempt to cast instance "entity.News@15dd910" to PersistenceCapable failed. Ensure that it has been enhanced.
FailedObject: entity.News@15dd910
    at org.apache.openjpa.kernel.BrokerImpl.assertPersistenceCapable(BrokerImpl.java:4353)
    at org.apache.openjpa.kernel.BrokerImpl.persist(BrokerImpl.java:2419)
    at org.apache.openjpa.kernel.BrokerImpl.persist(BrokerImpl.java:2280)
    at org.apache.openjpa.kernel.DelegatingBroker.persist(DelegatingBroker.java:1021)
    at org.apache.openjpa.persistence.EntityManagerImpl.persist(EntityManagerImpl.java:645)
    at dao.Test.main(Test.java:30)

请问这是那里出了问题。

我已经将openjpa包加入到项目里面。

问题补充：

xiaolongfeixiang 写道

persistence.xml中配置News这个实体类的信息。

这个好像没配！
请问要怎么配

问题补充：

mginobili 写道

lz有没有配置News对应的信息呢？

package entity;

// default package

import java.sql.Timestamp;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import static javax.persistence.GenerationType.IDENTITY;
import javax.persistence.Id;
import javax.persistence.Table;

/**
 * News entity. @author MyEclipse Persistence Tools
 */
@Entity
@Table(name = "news", catalog = "test")
public class News implements java.io.Serializable {

	// Fields

	private Integer id;
	private Integer type;
	private String username;
	private String content;
	private Timestamp time;
	private String ip;
	private Integer xianshi;

	// Constructors

	/** default constructor */
	public News() {
	}

	/** full constructor */
	public News(Integer type, String username, String content, Timestamp time,
			String ip, Integer xianshi) {
		this.type = type;
		this.username = username;
		this.content = content;
		this.time = time;
		this.ip = ip;
		this.xianshi = xianshi;
	}

	// Property accessors
	@Id
	@GeneratedValue(strategy = IDENTITY)
	@Column(name = "id", unique = true, nullable = false)
	public Integer getId() {
		return this.id;
	}

	public void setId(Integer id) {
		this.id = id;
	}

	@Column(name = "type")
	public Integer getType() {
		return this.type;
	}

	public void setType(Integer type) {
		this.type = type;
	}

	@Column(name = "username", length = 100)
	public String getUsername() {
		return this.username;
	}

	public void setUsername(String username) {
		this.username = username;
	}

	@Column(name = "content", length = 65535)
	public String getContent() {
		return this.content;
	}

	public void setContent(String content) {
		this.content = content;
	}

	@Column(name = "time", length = 19)
	public Timestamp getTime() {
		return this.time;
	}

	public void setTime(Timestamp time) {
		this.time = time;
	}

	@Column(name = "ip", length = 20)
	public String getIp() {
		return this.ip;
	}

	public void setIp(String ip) {
		this.ip = ip;
	}

	@Column(name = "xianshi")
	public Integer getXianshi() {
		return this.xianshi;
	}

	public void setXianshi(Integer xianshi) {
		this.xianshi = xianshi;
	}

}

问题补充：

xiaolongfeixiang 写道

<class>Entity.News</class>

<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/persistence
    http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0">
    
	<persistence-unit name="JPATestPU" transaction-type="RESOURCE_LOCAL">
		<provider>org.apache.openjpa.persistence.PersistenceProviderImpl</provider>
		<class>entity.News</class> 
  		<properties>
			<property name = "openjpa.ConnectionDriverName" value = "com.mysql.jdbc.Driver"/>
			<property name = "openjpa.ConnectionURL" value = "jdbc:mysql://localhost:3306/test"/>
			<property name = "openjpa.ConnectionUserName" value = "root"/>
			<property name = "openjpa.ConnectionPassword" value = "root"/>
	  	</properties>
	</persistence-unit>
	
</persistence>

还是不行：

250 JPATestPU INFO [main] openjpa.Runtime - Starting OpenJPA 1.2.0
750 JPATestPU INFO [main] openjpa.jdbc.JDBC - Using dictionary class "org.apache.openjpa.jdbc.sql.MySQLDictionary".
Exception in thread "main" <openjpa-1.2.0-r422266:683325 nonfatal user error> org.apache.openjpa.persistence.ArgumentException: Attempt to cast instance "entity.News@1d8c528" to PersistenceCapable failed. Ensure that it has been enhanced.
FailedObject: entity.News@1d8c528
at org.apache.openjpa.kernel.BrokerImpl.assertPersistenceCapable(BrokerImpl.java:4353)
at org.apache.openjpa.kernel.BrokerImpl.persist(BrokerImpl.java:2419)
at org.apache.openjpa.kernel.BrokerImpl.persist(BrokerImpl.java:2280)
at org.apache.openjpa.kernel.DelegatingBroker.persist(DelegatingBroker.java:1021)
at org.apache.openjpa.persistence.EntityManagerImpl.persist(EntityManagerImpl.java:645)
at dao.Test.main(Test.java:28)

问题补充：

xiaolongfeixiang 写道

在程序运行之前，对应的数据库、表，是否已经存在？

已经存在了！

问题补充：

xiaolongfeixiang 写道

检查下，是否是数据库表结构 与 实体映射的设置 是否一致

实体是用myeclipse 生成的。
这个应该不会有问题吧？

DAO

2010年1月29日 11:38

zhang116868
25
0 0 0

6个答案按时间排序按投票排序

0 0

检查下，是否是数据库表结构 与 实体映射的设置 是否一致

2010年2月01日 11:33

xiaolongfeixiang
3000
0 0 2

添加评论

0 0

在程序运行之前，对应的数据库、表，是否已经存在？

2010年1月29日 16:24

xiaolongfeixiang
3000
0 0 2

添加评论

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<?xml version="1.0" encoding="UTF-8"?> 
<persistence xmlns="http://java.sun.com/xml/ns/persistence" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xsi:schemaLocation="http://java.sun.com/xml/ns/persistence 
    http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0"> 
    
    <persistence-unit name="JPATestPU" transaction-type="RESOURCE_LOCAL"> 
        
<class>Entity.News</class>

<provider>org.apache.openjpa.persistence.PersistenceProviderImpl</provider> 
          <properties> 
            <property name = "openjpa.ConnectionDriverName" value = "com.mysql.jdbc.Driver"/> 
            <property name = "openjpa.ConnectionURL" value = "jdbc:mysql://localhost:3306/test"/> 
            <property name = "openjpa.ConnectionUserName" value = "root"/> 
            <property name = "openjpa.ConnectionPassword" value = "root"/> 
          </properties> 
    </persistence-unit> 
  
</persistence>

2010年1月29日 12:20

xiaolongfeixiang
3000
0 0 2