struts 标签中嵌套的问题，拜托高手抽出时间指点一下。Thanks

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struts 标签中嵌套的问题，拜托高手抽出时间指点一下。Thanks10

问题：我想输出一个订单集合 orders 中的信息，其中要输出客户customer的名字customer_name。查了一些资料，没有找到问题的答案。拜托高手抽出时间指点一下

<logic:iterate id="order" name="orders">
<%--
                Customer中定义了toString() 方法可以输出顾客的姓名
         --%>
<bean:write name="order" property="customer"/>

         <%--
               下面这样却不行。为什么？
          --%>
<bean:define id="c" name="order" property="customer" >
<bean:write name="c" property="customer_name" />
</bean:define>

</logic:iterate>

下面是异常信息:
javax.servlet.ServletException: Cannot find bean: "c" in any scope
org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:848)
org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:781)
org.apache.jsp.order.order_005flist_jsp._jspService(org.apache.jsp.order.order_005flist_jsp:240)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:97)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:322)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
org.apache.struts.action.RequestProcessor.doForward(RequestProcessor.java:1085)
org.apache.struts.action.RequestProcessor.processForwardConfig(RequestProcessor.java:398)
org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:241)
org.apache.struts.action.ActionServlet.process(ActionServlet.java:1196)
org.apache.struts.action.ActionServlet.doGet(ActionServlet.java:414)
javax.servlet.http.HttpServlet.service(HttpServlet.java:689)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)

问题补充：
我自己想到了

<bean:define id="c" name="order" property="customer" >
<bean:write name="c" property="customer_name" />
</bean:define>

改变如下：

<bean:define id="c" name="order" property="customer" /s>

<bean:write name="c" property="customer_name" />

Struts