QU66Q
- 浏览: 66213 次
- 性别:
- 来自: 北京
-
最新评论
文章列表
Java native关键字
- 博客分类：
- JAVA
native关键字说明其修饰的方法是一个原生态方法，方法对应的实现不是在当前文件，而是在用其他语言（如C和C++）实现的文件中。Java语言本身不能对操作系统底层进行访问和操作，但是可以通过JNI接口调用其他语言来实现对底层的访问。
JNI是Java本机接口（Java Native Interface），是一个本机编程接口，它是Java软件开发工具箱（java Software Development Kit，SDK）的一部分。JNI允许Java代码使用以其他语言编写的代码和代码库。Invocation API（JNI的一部分）可以用来将Java虚拟机（ ...
内存指令heppen-bebore
- 博客分类：
- JAVA
Java中，synchronized和lock是用来处理并发过程中，线程之间互斥关系，即被synchronized和lock修饰的变量或方法或代码段能保证同一时间有且只有一个线程在处理，这样可以保证其它线程能够处理最新的数据，而且数据在中途 ...
maven中把依赖的JAR包一起打包
- 博客分类：
- JAVA
转载：http://lvjun106.iteye.com/blog/1849803
这里所用到的MAVEN-PLUGIN是MAVNE-ASSEMBLY-PLUGIN
官方网站是:http://maven.apache.org/plugins/maven-assembly-plugin/usage.html
1. 添加此PLUGIN到项目的POM.XML中
Xml代码
<buizld>
<plugins>
Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level).
For example:Given binary tree [3,9,20,null,null,15,7],
3
/ \
9 20
/ \
15 7
return its level order traversal as:
[
[3],
[9,20],
[15,7]
]
# ...
Given an integer n, return the number of trailing zeroes in n!.
Note: Your solution should be in logarithmic time complexity.
class Solution(object):
def trailingZeroes(self, n):
"""
:type n: int
:rtype: int
"""
resul ...
You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
class Solution(object):
def climbStairs(self, n):
"""
:type n: int
:rtype: int
...
Write a program to check whether a given number is an ugly number.
Ugly numbers are positive numbers whose prime factors only include 2, 3, 5. For example, 6, 8 are ugly while 14 is not ugly since it includes another prime factor 7.
Note that 1 is typically treated as an ugly number.
class Solut ...
Given a sorted linked list, delete all duplicates such that each element appear only once.
For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3.
# Definition for singly-linked list.
# class ListNode(object):
# def __init__(self, x):
# ...
Write an algorithm to determine if a number is "happy".
A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or i ...
Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight).
For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should return 3.
class Solution(object):
def hammingW ...
Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.
According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a no ...
Given an integer, write a function to determine if it is a power of three.
Follow up:
Could you do it without using any loop / recursion?
class Solution(object):
def isPowerOfThree(self, n):
"""
:type n: int
:rtype: bool
""&quo ...
Given an integer, write a function to determine if it is a power of two.
class Solution(object):
def isPowerOfTwo(self, n):
"""
:type n: int
:rtype: bool
"""
return True if not n&(n-1) and n != 0 else False
Python中的matplotlib画图总结
- 博客分类：
- Python
# -*- coding: utf-8 -*-
import matplotlib.pyplot as plt
from numpy.random import randn
import numpy as np
from io import StringIO
import pandas as pd
'''
#Create figure
fig = plt.figure()
#创建子图subplot: 表示2X2，即4个子图中的第1个图，编号为1
#参数：nrows, ncols, sharex(所有子图是否使用相同的x轴)，sharey，subplot_kw( ...
Reverse a singly linked list.
# Definition for singly-linked list.
# class ListNode(object):
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution(object):
def reverseList(self, head):
"""
:type head: ListNode
...