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合并两个已排好序的数组, Merge算法将会用于下一节的自底向上合并排序算法。 #include <stdio.h> #include <iostream.h> #include <stdlib.h> #define Low 0 #define Middle 3 #define High 10 int main(void) {     int A[High+1] = {2,11,45,57,3,6,13,24,25,65,68};     int B[High+1] = {0,0,0,0,0,0,0,0,0,0,0};     int low = 0;   ...
#include <stdio.h> #include <iostream.h> #include <stdlib.h> #define N 10 int main(void) {     int a[N] = {10,9,8,7,6,5,4,3,2,1};     for(int i=0;i<N-1;i++)     {         int k = i;         for(int j=i+1;j<N;j++)         {             if(a[j] < a[k])               k = j;   ...
#include <stdio.h> #include <iostream.h> #include <stdlib.h> #define N 10 int main(void) {     int a[N] = {10,9,8,7,6,5,4,3,2,1};     for(int i=1;i<N;i++)     {        int temp = a[i];        int j = i-1;        while(j>=0 && a[j]>temp)        {            a[j+1] = ...
#include <stdio.h> #include <iostream.h> #include <stdlib.h> #define Max 255 #define N 3 int main(void) {    int D[N][N] = {{0,2,9},{8,0,6},{1,Max,0}};    cout<<"Original D is : \n";    for(int i =0;i<N;i++)    {       for(int j=0;j<N;j++)           cout<& ...

8queen

#include <stdio.h> #include <iostream.h> #define QueenNum 8 void output(int solution[QueenNum]) { for(int i=0;i<QueenNum;i++) { cout<<solution[i]<<" "; } cout<<"\n"; } int judge(int solution[QueenNum]) { for(int i=0;i<QueenNum;i++) { ...
#include <stdio.h> #include <iostream.h> #include <stdlib.h> #include <string.h> #define A "xyxxzxyzxy" #define B "zxzyyzxxyxxz" void output(char str[]) {      for(int i=0;i<strlen(str);i++)          cout<<str[i]<<" ";      cout&l ...
题目:四种类型的物品,体积分别为2,3,5,6,价值分别为4,7,9,11.背包容量为8,每种物品的最大数量不限制 #include <iostream> using namespace std; #define MAXSIZE 8 #define NUM 4 int main(void) {     int size_value[NUM+1][2] = {{0,0},{2,4},{3,7},{5,9},{6,11}};     int solution[NUM+1][MAXSIZE+1];     int v[NUM+1];     for(int p=0;p<= ...
题目:容量为9的背包,有4种物品,体积分别为2,3,4,5,价值分别为3,4,5,7,求能放进背包的最大值。 #include <iostream> using namespace std; #define MAXSIZE 9 #define NUM 4 int main(void) {     int size_value[5][2] = { {0,0},{2,3},{3,4},{4,5},{5,7} };     int solution[NUM + 1][MAXSIZE +1];     for(int p=0;p<=NUM;p++)     { ...
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