common-uploadfiles.1.2版本

servlet中测试成功:

java 代码

String filesystempath = request.getSession().getServletContext().getRealPath("/");
ServletRequestContext srcontext = new ServletRequestContext(request);
System.out.println(srcontext.getCharacterEncoding());
System.out.println(srcontext.getContentType());
boolean isMultipart = ServletFileUpload.isMultipartContent(request);
if (isMultipart) {
    ServletFileUpload upload = new ServletFileUpload();
    try {
//Parse the request
    FileItemIterator iter = upload.getItemIterator(request);
    while (iter.hasNext()) {
        FileItemStream item = iter.next();
        //System.out.println(item.getContentType());
        InputStream stream = item.openStream();
        if (item.isFormField()) {
                                           //这里处理form中的其它表单域内容
        } else {
                                           //这里处理上传对象
        String clientrealpath = item.getName();
        clientrealpath = clientrealpath.replace("\\", "\\\\");
//System.out.println(clientrealpath);
String filename = StringHelper.getFileName(clientrealpath);
//System.out.println(filesystempath+filename);
File newfile = new File(filesystempath+filename);
OutputStream os =new FileOutputStream(newfile);
byte[] b = new byte[8192];
int len;
while ((len = stream.read(b)) != -1) {
os.write(b, 0, len);
os.flush();
os.close();
stream.close();
// Process the input stream
}
}
} catch (FileUploadException e) {
e.printStackTrace();
}
}

分享到：

oracle procedure 自定义类型 | 显示隐藏层

• 2007-07-08 15:13
• 浏览 1586
• 评论(1)
• 查看更多

评论

1 楼 xuey210 2009-10-31  

struts 的action 中一定不能成功