HashSet remove 报错 contains true

求助：HashSet 包含某Object=true，但是remove该Object就报错。Object RecordNumber重写了toString hashCode equals 方法。估计是这里有问题，请教各位大侠。

import java.text.ParseException;
import java.util.Date;
//数据源 表名 时间 (记录数量)
public class RecordNumber {
    public final static int CSUDF_SYS_CELL_HOUR_G = (int) 0;
    public final static int CSUDF_SYS_RTF_HOUR_G = (int) 1;
    public final static int CSUDF_SYS_GPROC_HOUR_G = (int) 2;
    private String OMC;
    private String TableName;
    private Date DateTime;
    public RecordNumber(String DataSource, String TableName, Date DateTime) {
        this.OMC = DataSource;
        this.TableName = TableName;
        this.DateTime = DateTime;
    }
    public String getOMC() {
        return this.OMC;
    }
    public String getTableName() {
        return this.TableName;
    }
    public Date getDateTime() {
        return this.DateTime;
    }
    public int getTableNameInt() {
        int x = 1000;
        if (TableName.equals("CSUDF_SYS_CELL_HOUR_G")) {
            x = (int) CSUDF_SYS_CELL_HOUR_G;
        }
        if (TableName.equals("CSUDF_SYS_RTF_HOUR_G")) {
            x = CSUDF_SYS_RTF_HOUR_G;
        }
        if (TableName.equals("CSUDF_SYS_GPROC_HOUR_G")) {
            x = CSUDF_SYS_GPROC_HOUR_G;
        }
        return x;
    }
    @Override
    public String toString() {
        return (this.OMC + "," + this.TableName + "," + this.DateTime);
    }
    @Override
    public boolean equals(Object o) {
        return (o instanceof RecordNumber)
                && toString().equals(((RecordNumber) o).toString());
    }
    @Override
    public int hashCode() {
        int hash = 7;
        hash = 37 * hash + (this.OMC != null ? this.OMC.hashCode() : 0);
        hash = 37 * hash + (this.TableName != null ? this.TableName.hashCode() : 0);
        hash = 37 * hash + (this.DateTime != null ? this.DateTime.hashCode() : 0);
        return hash;
    }
    //单元测试
    public static void main(String[] args) throws ParseException {
        java.text.DateFormat df = new java.text.SimpleDateFormat("yyyy-MM-dd HH:mm");
        RecordNumber rn = new RecordNumber("OMCSP9", "CSUDF_SYS_CELL_HOUR_G", df.parse("2010-10-26 07:00"));
        java.util.Set<RecordNumber> testSet = new java.util.LinkedHashSet<RecordNumber>();
        testSet.add(rn);
        rn = new RecordNumber("OMCSP1", "CSUDF_SYS_CELL_HOUR_G", df.parse("2010-10-26 07:00"));
        testSet.add(rn);
        rn = new RecordNumber("OMCSP11", "CSUDF_SYS_CELL_HOUR_G", df.parse("2010-10-26 07:00"));
        testSet.add(rn);
        System.out.println(testSet.size());
        for (RecordNumber x : testSet) {
            System.out.println(x);
            System.out.println("testSet包含该RecordNumber：" + testSet.contains(x));
            testSet.remove(x);
            System.out.println(testSet.size());
        }
    }
}




run：
3
OMCSP9,CSUDF_SYS_CELL_HOUR_G,Tue Oct 26 07:00:00 CST 2010
testSet包含该RecordNumber：true
2
Exception in thread "main" java.util.ConcurrentModificationException
        at java.util.LinkedHashMap$LinkedHashIterator.nextEntry(LinkedHashMap.java:373)
        at java.util.LinkedHashMap$KeyIterator.next(LinkedHashMap.java:384)
        at datatransfer.RecordNumber.main(RecordNumber.java:79)
Java Result: 1
成功生成（总时间：0 秒）

评论

1 楼 DataBird 2010-11-07  

使用迭代器可以顺利删除。至于为什么就懒得管了。
  Iterator<RecordNumber> it = testSet.iterator();
        while (it.hasNext()) {...  it.remove();  ...}