ajaxanywhere+struts

不知道是不是浏览器的问题.list.jsp页面定义的刷新区域总是刷新不了.请各位帮忙看看.

评论

5 楼 javalwd 2007-05-10  

好好.

4 楼 menglinxi 2007-05-09  

<br/>
<strong>shihukui 写道：</strong><br/>
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<p>我将结果放在request里面也是可以的，你仔细检查下你的程序吧</p>
<p>还有你程序里面数据库链接什么的都没有关闭哦 <img src='/javascripts/fckeditor/editor/images/smiley/msn/regular_smile.gif' alt=''/></p>
<p> </p>
<p>呵呵，兄弟好好看我整个例子的流程。数据库关闭了。哈哈。</p>
<p>我再仔细看看我的程序吧。呵呵。</p>
<p> </p>
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3 楼 shihukui 2007-05-08  

<p>我将结果放在request里面也是可以的，你仔细检查下你的程序吧</p>
<p>还有你程序里面数据库链接什么的都没有关闭哦 <img src='/javascripts/fckeditor/editor/images/smiley/msn/regular_smile.gif' alt=''/></p>
<p> </p>

2 楼 menglinxi 2007-05-08  

<br/>
<strong>shihukui 写道：</strong><br/>
<div class='quote_div'>
<p>在ListForm中要增加 List类型的result变量</p>
<p>为什么要这样呢?</p>
<p>Action中要执行查询数据后保存至result后再跳转至输入页面</p>
<p><font>你的例子中用的<font>public ActionForward userList(ActionMapping mapping, ActionForm actionForm,<br/>
   HttpServletRequest request, HttpServletResponse response)<br/>
   throws Exception {<br/>
  <br/>
  DynaActionForm form = (DynaActionForm)actionForm;<br/>
  <br/>
  //Conn test = new Conn();<br/>
  <br/>
  Connection conn = test.getConn();<br/>
  <br/>
  java.sql.Statement stmt = conn.createStatement();<br/>
  <br/>
  java.sql.ResultSet rs = stmt.executeQuery("select * from users");<br/>
  <br/>
  List&lt;userbean&gt;&lt;/userbean&gt; result = new ArrayList&lt;userbean&gt;&lt;/userbean&gt;();<br/>
  <br/>
  try {<br/>
   if (rs != null) {<br/>
    while (rs.next()) {<br/>
     UserBean userBean = new UserBean();<br/>
     <br/>
     userBean.setId(rs.getLong("id"));<br/>
     userBean.setName(rs.getString("name"));<br/>
     userBean.setPassword(rs.getString("password"));<br/>
     <br/>
     result.add(userBean);<br/>
    }<br/>
   }<br/>
  } catch (java.sql.SQLException e) {<br/>
   e.printStackTrace();<br/>
  } finally {<br/>
   rs.close();<br/>
   <br/>
   stmt.close();<br/>
   <br/>
   conn.close();<br/>
  }<br/>
  <br/>
  // 返回查询结果<br/>
  form.set("result", result);<br/>
  return mapping.findForward("userList");<br/>
 }</font></font></p>
<p>返回的list是包含的UserBean对象;</p>
<p><font><font>我的程序： </font></font></p>
<p><font><font> public List getList()<br/>
        throws SQLException<br/>
    {<br/>
        ConnectDBBean db;<br/>
        List list;<br/>
        String sql;<br/>
        db = new ConnectDBBean();<br/>
        list = new ArrayList();<br/>
        sql = "select id,name,sex,[work],address from book  order by id desc";<br/>
        try<br/>
        {<br/>
            Connection con = db.getConnection();<br/>
            Statement stmt = con.createStatement();<br/>
            Book bean;<br/>
            for(ResultSet rs = stmt.executeQuery(sql); rs.next(); list.add(bean))<br/>
            {<br/>
                bean = new Book();<br/>
                bean.setId(rs.getString(1));<br/>
                bean.setName(rs.getString(2));<br/>
                bean.setSex(rs.getString(3));<br/>
                bean.setWork(rs.getString(4));<br/>
                bean.setAddress(rs.getString(5));<br/>
            }</font></font>  </p>
<p> </p>
<p><font>        }<br/>
        catch(SQLException e)<br/>
        {<br/>
            e.printStackTrace();<br/>
            throw e;<br/>
        }       <br/>
        return list;</font></p>
<p>}</p>
<p><font>返回的也是list里面也是包含bean对象的．</font></p>
<p><font>不同的是我用这个</font></p>
<p><font>request.setAttribute("result", list);把list放入result</font></p>
<p>然后用<font> return mapping.findForward("list");返回到页面．</font></p>
<p>而你用的是<font>  form.set("result", result);<br/>
  return mapping.findForward("userList");区别就在这里．搞不懂为什么非要在listForm中加个List类型的result变量？<img src='http://www.iteye.com/javascripts/fckeditor/editor/images/smiley/msn/embaressed_smile.gif' alt=''/></font></p>
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1 楼 shihukui 2007-05-08  

<p>在ListForm中要增加 List类型的result变量</p>
<p>Action中要执行查询数据后保存至result后再跳转至输入页面</p>