如何输出两个字符串数组中的相同元素

比如说：现有两个数组  String []s1=  { "1","22","34","55","5"};
                                String []s2=  { "22","2","34","255","52"};

 

   如何输出他们拥有的相同的元素22，34，并将其放入新的数组中。

评论

4 楼 ahlon 2009-12-03  

apache commons collections framework

CollectionUtil.intersection(java.util.Collection a, java.util.Collection b)

Returns a Collection containing the intersection of the given Collections.

http://commons.apache.org/collections/

3 楼 wsh303496225 2009-12-03  

//两个循环就解决了
String [] result=new String[10]//(忘了怎么定义数组了...不知道支不支持动态数组..)
//不行的话,就用集合就行了
//ArrayList list=new ArrayList();
int a=0;
for(int i=0;i<s1.length;i++){
 for(int j=0;j<s2.length;j++){
    if(s1[i]=s2[j]) {
        result[a++]=s2[j];//如果用集合改成这样的就行了:list.add(s2[j]);
}
}
}

2 楼 Hooopo 2009-12-03  

ruby里也可以不用集合..........

irb(main):027:0> [1,2,3] - ([1,2,3] - [1,2])
=> [1, 2]

1 楼 Hooopo 2009-12-03  

用集合啊~~

irb(main):021:0> require 'set'
=> false
irb(main):022:0> ([1,2,3].to_set & [2,3,4].to_set).to_a
=> [2, 3]