int类型与四位字节数组互转(java)

原文：http://topic.csdn.net/u/20070606/12/7cd05c3e-71da-42ff-b218-4fd0482f253b.html

 

package com.mapabc.sz_hbt.util;
/**
 * <p>Title:整型与长度为4的字节数组的互换 </p>
 * <p>Description: </p>
 * <p>Copyright: Copyright (c) 2007-5-10</p>
 * <p>Company: www.mapabc.com</p>
 * @author luoyj
 * @version 1.0
 */   
public class ByteUtil {
    /**
     * 整型转换为4位字节数组
     * @param intValue
     * @return
     */
    public static byte[] int2Byte(int intValue) {
        byte[] b = new byte[4];
        for (int i = 0; i < 4; i++) {
            b[i] = (byte) (intValue >> 8 * (3 - i) & 0xFF);
            //System.out.print(Integer.toBinaryString(b[i])+" ");
            //System.out.print((b[i] & 0xFF) + " ");
        }
        return b;
    }
    /**
     * 4位字节数组转换为整型
     * @param b
     * @return
     */
    public static int byte2Int(byte[] b) {
        int intValue = 0;
//        int tempValue = 0xFF;
        for (int i = 0; i < b.length; i++) {
            intValue += (b[i] & 0xFF) << (8 * (3 - i));
            // System.out.print(Integer.toBinaryString(intValue)+" ");
        }
        return intValue;
    }

}

 

 

评论

2 楼 nextw3 2010-11-16  

b[i] = (byte) (intValue >> 8 * (3 - i) & 0xFF);

写成

b[i] = (byte) (intValue >> 8 * (3 - i));

应该也没问题吧？

1 楼 luxiaoshuai 2010-04-05  

[b][/b][i][/i][u][/u]

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