spring jws开发 webservice

及其简单：

@WebService(serviceName = "LoginService")
@SOAPBinding(parameterStyle=ParameterStyle.BARE)
public class LoginServiceEndpoint {
	@WebMethod
	public String helloworld(String name) {
		return "hello:" + name;
	}
}
<bean class="org.springframework.remoting.jaxws.SimpleJaxWsServiceExporter">
		<property name="baseAddress" value="http://localhost:9999/" />
	</bean>
	<bean id="loginServiceEndpoint" class="com.doze.data.service.LoginServiceEndpoint">
	</bean>	

通过http://localhost:9999/LoginService?wsdl访问webservice部署描述符
还有自动生成的xsd:http://localhost:9999/LoginService?xsd=1

@SOAPBinding(parameterStyle=ParameterStyle.BARE)必须添加，否则会报错。

评论

2 楼 KimShen 2009-06-30  

package service;
import javax.jws.WebService;
import javax.jws.soap.SOAPBinding;
@WebService(serviceName = "userService")
@SOAPBinding(parameterStyle=javax.jws.soap.SOAPBinding.ParameterStyle.BARE)    
public class UserSerivce implements UserServiceInterface{
public void testMethod() {
System.out.println("in method");
}
}

<bean class="org.springframework.remoting.jaxws.SimpleJaxWsServiceExporter">
<property name="baseAddress" value="http://localhost:9999/" />
</bean>
<bean id="userService" class="service.UserSerivce" />

如何访问到wsdl?
http://127.0.0.1:9999/userService?wsdl
?
貌似不行啊 请问如何访问到wsdl文件啊

另外SimpleJaxWsServiceExporter是否需要WEB服务器？还是单机就可以

1 楼 96sd2 2009-04-24  

多谢文章提醒