python ElementTree解析xml小记

   学python没多久,遇到一个解析xml的需求，边学边练，用的是ElementTree，感觉没有说的那么方便，也许E文不好，看漏api,root.findall()搞的象正则表达式，瞎了。希望知道的朋友告诉我

 

    题目这样，比如有个xml：

<?xml version="1.0" encoding="UTF-8"?>
<students>
    <student no="2009081097">
        <name>Hongten</name>
        <gender>M</gender>
        <age>20</age>
        <score subject="math">97</score>
        <score subject="chinese">90</score>
    </student>
    <student no="2009081098">
        <name>DuDu</name>
        <gender>W</gender>
        <age>21</age>
        <score subject="math">87</score>
        <score subject="chinese">96</score>
    </student>
    <student no="2009081099">
        <name>Sum</name>
        <gender>M</gender>
        <age>19</age>
        <score subject="math">64</score>
        <score subject="chinese">98</score>
    </student>
</students>

    已知某个值是19，求拥有该值的节点的父节点的所有子节点，就是这么一块：

        <name>Sum</name>
        <gender>M</gender>
        <age>19</age>
        <score subject="math">64</score>
        <score subject="chinese">98</score>

 

    我的代码：

#coding=utf-8
import os
import xml.etree.ElementTree as ET

filepath = 'c:\\test\\a.xml'
tree = ET.parse(filepath)
root = tree.getroot()

p_node = None
r_node = []

def func(node):
	global p_node
	if len(node)>0:
		p_node = node
		for c in node:
			func(c)
	else:
		if node.text == '19':#值在这里在这里
			r_node.append(p_node)

if __name__ == '__main__':
	func(root)
	if not r_node:
		for n in r_node:
			print '-'*10
			for c in n:
				print c.tag,c.text
	else:
		print 'not found'		

   输出：

----------
name Sum
gender M
age 19
score 64
score 98
[Finished in 0.1s]

    先这样吧，交差！

评论

1 楼 longhua2003 2015-11-26