HttpClient通过HttpPost传递参数

HttpClient新版本（新老版本没有做明确界定，Sorry!）

package http;

import java.util.ArrayList;
import java.util.List;

import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;

public class HttpTests {

	/**
	 * @param args
	 * @throws Exception
	 */
	public static void main(String[] args) throws Exception {
		HttpClient httpclient = new DefaultHttpClient();
		HttpPost httpPost = new HttpPost("******/abc");
		List<NameValuePair> nvps = new ArrayList<NameValuePair>();
		nvps.add(new BasicNameValuePair("username", "vip"));
		nvps.add(new BasicNameValuePair("password", "secret"));
		httpPost.setEntity(new UrlEncodedFormEntity(nvps));
		httpclient.execute(httpPost);
		httpclient.getConnectionManager().shutdown();
	}

}

HttpClient 老版本：

package http;

import org.apache.commons.httpclient.HttpClient;
import org.apache.commons.httpclient.NameValuePair;
import org.apache.commons.httpclient.methods.PostMethod;

public class HttpTests {

	/**
	 * @param args
	 * @throws Exception
	 */
	public static void main(String[] args) throws Exception {
		HttpClient httpclient = new HttpClient();
		PostMethod httpPost =new PostMethod("******/abc");
        NameValuePair[] param = { new NameValuePair("username", "vip")};
        httpPost.setRequestBody(param); 
		httpclient.executeMethod(httpPost);
	}

}

评论

2 楼 Imini123 2015-10-26  

     

1 楼 l1334388165 2015-09-24  

为什么用了第一种，死都没用呢？