disruptor3.x 简单例子

这个是最新的 disruptor3的例子....来自官方代码稍微简化后的

 

 

package io.grass.core.collect;

import static com.lmax.disruptor.RingBuffer.createSingleProducer;

import java.util.concurrent.CountDownLatch;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;

import org.slf4j.Logger;
import org.slf4j.LoggerFactory;

import com.lmax.disruptor.BatchEventProcessor;
import com.lmax.disruptor.EventFactory;
import com.lmax.disruptor.EventHandler;
import com.lmax.disruptor.RingBuffer;
import com.lmax.disruptor.SequenceBarrier;
import com.lmax.disruptor.YieldingWaitStrategy;
import com.lmax.disruptor.util.PaddedLong;

/**
 * 简单测试
 * 
 * @author zuoge85
 * 
 */
public class DisruptorBaseTest {
	protected static final Logger log = LoggerFactory.getLogger(DisruptorBaseTest.class);
	
	private static final int THREAD_NUMS = 1;
	private static final int BUFFER_SIZE = 1024 * 8;
	private static final long NUMS = 1000_000_00L;

	public static void main(String[] args) throws InterruptedException {
		RingBuffer<MessageEvent> ringBuffer = createSingleProducer(
				MessageEvent.EVENT_FACTORY, BUFFER_SIZE,
				new YieldingWaitStrategy());
		ExecutorService executors = Executors.newFixedThreadPool(THREAD_NUMS);
		SequenceBarrier sequenceBarrier = ringBuffer.newBarrier();

		MessageMutationEventHandler[] handlers = new MessageMutationEventHandler[THREAD_NUMS];
		BatchEventProcessor<?>[] batchEventProcessors = new BatchEventProcessor[THREAD_NUMS];

		for (int i = 0; i < THREAD_NUMS; i++) {
			handlers[i] = new MessageMutationEventHandler();
			batchEventProcessors[i] = new BatchEventProcessor<MessageEvent>(
					ringBuffer, sequenceBarrier, handlers[i]);
			ringBuffer
					.addGatingSequences(batchEventProcessors[i].getSequence());
		}

		CountDownLatch latch = new CountDownLatch(THREAD_NUMS);
		for (int i = 0; i < THREAD_NUMS; i++) {
			long n =  batchEventProcessors[i].getSequence().get() + NUMS;
			System.out.println(n +"    "  +NUMS+"  "+batchEventProcessors[i].getSequence().get() );
			handlers[i].reset(latch, n);
			executors.submit(batchEventProcessors[i]);
		}
		long start = System.currentTimeMillis();

		for (long i = 0; i < NUMS; i++) {
			long sequence = ringBuffer.next();
			ringBuffer.get(sequence).setValue(i);
			ringBuffer.publish(sequence);
		}

		latch.await();
		long opsPerSecond = (NUMS * 1000L)
				/ (System.currentTimeMillis() - start);

		for (int i = 0; i < THREAD_NUMS; i++) {
			batchEventProcessors[i].halt();
			if ((NUMS - 1) == handlers[i].getValue()) {

			} else {
				log.error("error");
			}
		}
		executors.shutdown();
		log.info(String.format("Run %d, Disruptor=%,d ops/sec%n", 1, opsPerSecond));
	}

	public static final class MessageMutationEventHandler implements
			EventHandler<MessageEvent> {
		private final PaddedLong value = new PaddedLong();
		private long count;
		private CountDownLatch latch;

		public MessageMutationEventHandler() {
			
		}

		public long getValue() {
			return value.get();
		}

		public void reset(final CountDownLatch latch, final long expectedCount) {
			value.set(0L);
			this.latch = latch;
			count = expectedCount;
		}

		@Override
		public void onEvent(final MessageEvent event, final long sequence,
				final boolean endOfBatch) throws Exception {
			//log.info("onEvent:{}",event.getValue());
			value.set(event.getValue());
			if (count == sequence) {
				latch.countDown();
			}
		}
	}

	public static final class MessageEvent {
		private long value;

		public long getValue() {
			return value;
		}

		public void setValue(final long value) {
			this.value = value;
		}

		public final static EventFactory<MessageEvent> EVENT_FACTORY = new EventFactory<MessageEvent>() {
			public MessageEvent newInstance() {
				return new MessageEvent();
			}
		};
	}
}

 

 

评论

2 楼 heipacker 2014-01-05  

什么玩意，你运行过你的代码？

1 楼 hanqian200705 2013-08-25  

请问如果是线程并发消费Event的需要怎么处理？ 改THREAD_NUMS>1 后好像会出现多个线程消费同一个Event的情况