sybase iq分组排序取前N名

营业部客户资产前5客户语句

select
*
from
(
	select 
	*
	from #ADO_TEMP
)t1 where exists
(
	select count(1) from #ADO_TEMP t2 where t1.营业部=t2.营业部 and t1.总资产>t2.总资产
	having count(1)<5
) order by t1.营业部,t1.总资产 desc
;

oracle可以用rank()函数，sybaseiq也有rank()，但是我那机器版本不支持
rank() over(partition by t2.org_full_name order by t1.总资产 desc) pm