MongoDB 模糊查询的三种实现方式-morphia实现

MongoDB 模糊查询的三种实现方式-morphia实现如下：

方式一：正则表达式-单个值模糊查询

 

 

Pattern pattern = Pattern.compile("^" + treeIndex + ".*$", Pattern.CASE_INSENSITIVE);

assetInfoDao.createQuery().filter("treeIndexes", pattern);

方式二：正则表达式-多个值模糊查询

 

String[] categorys = category.split(",");

List<Pattern> patterns = Lists.newArrayList();

for (String treeIndex : categorys) {

Pattern pattern = Pattern.compile("^" + treeIndex + ".*$", Pattern.CASE_INSENSITIVE);

patterns.add(pattern);

}

query.filter("treeIndexes all", patterns);

方式三：contains模糊查询方式

 

if (StringUtils.isNotBlank(title)) {

query = query.field("title").contains(title);

}

方式四：精确查询

 

String[] categorys = category.split(",");

query.filter("treeIndexes all", Arrays.asList(categorys));

 

imports:

import java.util.regex.Pattern;

import com.google.code.morphia.DatastoreImpl;

import com.google.code.morphia.query.Query;

 

PS:

/**

* <p>Create a filter based on the specified condition and value.

* </p><p>

* <b>Note</b>: Property is in the form of "name op" ("age >").

* </p><p>

* Valid operators are ["=", "==","!=", "<>", ">", "<", ">=", "<=", "in", "nin", "all", "size", "exists"]

* </p>

* <p>Examples:</p>

* 

* <ul>

* <li>{@code filter("yearsOfOperation >", 5)}</li>

* <li>{@code filter("rooms.maxBeds >=", 2)}</li>

* <li>{@code filter("rooms.bathrooms exists", 1)}</li>

* <li>{@code filter("stars in", new Long[]{3,4}) //3 and 4 stars (midrange?)}</li>

* <li>{@code filter("age >=", age)}</li>

* <li>{@code filter("age =", age)}</li>

* <li>{@code filter("age", age)} (if no operator, = is assumed)</li>

* <li>{@code filter("age !=", age)}</li>

* <li>{@code filter("age in", ageList)}</li>

* <li>{@code filter("customers.loyaltyYears in", yearsList)}</li>

* </ul>

* 

* <p>You can filter on id properties <strong>if</strong> this query is

* restricted to a Class<T>.

*/

 

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1 楼 用户名不存在 2012-09-25  

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