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锁定老帖子 主题:将阿拉伯数字转换成中文金额大写
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发表时间:2011-03-05
将数字转换成中文金额大写形式(Java版),写得很不错,我也来写一个,我觉得这个算法比其更简单有效。闲话少说,大家看代码吧,代码很简单。
前段时间在javaeye上看到一篇关于将数字转换成中文金额大写文章:import java.util.Scanner; import java.util.regex.Matcher; import java.util.regex.Pattern; public class CurrencyConverter { private static final double MAXIMUM_NUMBER = 9999999999999.99d; private static final String CN_ZERO = "零"; private static final String CN_SYMBOL = "¥:"; private static final String CN_DOLLAR = "圆"; private static final String CN_INTEGER = "整"; private static final String[] digits = new String[] { "零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖" }; private static final String[] radices = new String[] { "", "拾", "佰", "仟" }; private static final String[] bigRadices = new String[] { "", "万", "亿", "万" }; private static final String[] decimals = new String[] { "角", "分" }; public static void main(String[] args) { // 键盘输入数字 String currencyDigits = input(); // 检查数字合法性 if (check(currencyDigits)) { //转换大写并输出 System.out.println(convert(currencyDigits)); } } /** * 转换大写 * * @param currencyDigits * @return */ public static String convert(String currencyDigits) { String integral = null; // 整数部分 String decimal = null; // 小数部分 String outputCharacters = null; // 最终转换输出结果 String d = null; int zeroCount = 0, p = 0, quotient = 0, modulus = 0; // 删除数字中的逗号, currencyDigits = currencyDigits.replace("/,/g", ""); // 删除数字左边的0 currencyDigits = currencyDigits.replace("/^0+/", ""); // 拆分数字中的整数与小数部分 String[] parts = currencyDigits.split("\\."); if (parts.length > 1) { integral = parts[0]; decimal = parts[1]; // 如果小数部分长度大于2,四舍五入,保留两位小数 if (decimal.length() > 2) { long dd = Math.round(Double.parseDouble("0."+decimal) * 100) ; decimal = Long.toString(dd); } } else { integral = parts[0]; decimal = "0"; } // Start processing: outputCharacters = ""; // Process integral part if it is larger than 0: if (Double.parseDouble(integral) > 0) { zeroCount = 0; for (int i = 0; i < integral.length(); i++) { p = integral.length() - i - 1; d = integral.substring(i, i + 1); quotient = p / 4; modulus = p % 4; if (d.equals("0")) { zeroCount++; } else { if (zeroCount > 0) { outputCharacters += digits[0]; } zeroCount = 0; outputCharacters += digits[Integer.parseInt(d)] + radices[modulus]; } if (modulus == 0 && zeroCount < 4) { outputCharacters += bigRadices[quotient]; } } outputCharacters += CN_DOLLAR; } // Process decimal part if it is larger than 0: if (Double.parseDouble(decimal) > 0) { for (int i = 0; i < decimal.length(); i++) { d = decimal.substring(i, i + 1); if (!d.equals("0")) { outputCharacters += digits[Integer.parseInt(d)] + decimals[i]; } else { if (i == 0) { outputCharacters += CN_ZERO; } } } } // Confirm and return the final output string: if (outputCharacters.equals("")) { outputCharacters = CN_ZERO + CN_DOLLAR; } if (decimal == null || decimal.equals("0")) { outputCharacters += CN_INTEGER; } outputCharacters = CN_SYMBOL + outputCharacters; return outputCharacters; } /** * 从键盘输入要转换的数字 * * @return */ private static String input() { System.out.println("请输入一个数字(精确到小数点后两位):"); Scanner scanner = new Scanner(System.in); String currencyDigits = scanner.next(); scanner.close(); return currencyDigits; } /** * 检查输入数字的合法性 * * @param currencyDigits * @return */ private static boolean check(final String currencyDigits) { if (currencyDigits == null || currencyDigits.trim().equals("")) { System.out.println("没有输入要转换的数字"); return false; } Pattern pattern = Pattern.compile("/[^,.\\d]/", Pattern.CASE_INSENSITIVE); Matcher matcher = pattern.matcher(currencyDigits); if (matcher.find()) { System.out.println("数字中含有非法字符!"); return false; } pattern = Pattern.compile("/^((\\d{1,3}(,\\d{3})*(.((\\d{3},)*\\d{1,3}))?)|(\\d+(.\\d+)?))$/", Pattern.CASE_INSENSITIVE); matcher = pattern.matcher(currencyDigits); if (matcher.find()) { System.out.println("错误的数字格式!"); return false; } if (Double.parseDouble(currencyDigits) > MAXIMUM_NUMBER) { System.out.println("超出转换最大范围!"); return false; } return true; } } 声明:ITeye文章版权属于作者,受法律保护。没有作者书面许可不得转载。
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发表时间:2011-04-17
建议看看这个代码
http://bardo.iteye.com/admin/blogs/983559 |
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发表时间:2011-04-17
恩,就是注释少了点,有点看不懂,本人新手~
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发表时间:2011-07-21
参考了一个前辈写的,代码如下:
import java.util.Scanner; public class MoneyConvert { static Scanner san = new Scanner(System.in); private static String HanDigiStr[] = new String[] { "零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖" }; private static String HanDiviStr[] = new String[] { "", "拾", "佰", "仟", "万", "拾", "佰", "仟", "亿", "拾", "佰", "仟", "万", "拾", "佰", "仟", "亿", "拾", "佰", "仟", "万", "拾", "佰", "仟" }; public static void main(String[] args) { System.out.println("请输入一个要转化的值:"); double db = san.nextDouble(); System.out.println(NumToRMBStr(db)); } public static String NumToRMBStr(double val) { String SignStr = ""; String TailStr = ""; long fraction, integer; int jiao, fen; if (val < 0) { val = -val; SignStr = "负"; } if (val > 99999999999999.999 || val < -99999999999999.999) return "数值位数过大!"; // 四舍五入到分 long temp = Math.round(val * 100); integer = temp / 100; fraction = temp % 100; jiao = (int) fraction / 10; fen = (int) fraction % 10; if (jiao == 0 && fen == 0) { TailStr = "整"; } else { TailStr = HanDigiStr[jiao]; if (jiao != 0) TailStr += "角"; if (integer == 0 && jiao == 0) // 零元后不写零几分 TailStr = ""; if (fen != 0) TailStr += HanDigiStr[fen] + "分"; } // 下一行可用于非正规金融场合,0.03只显示“叁分”而不是“零元叁分” // if( !integer ) return SignStr+TailStr; return "¥" + SignStr + PositiveIntegerToHanStr(String.valueOf(integer)) + "元" + TailStr; } private static String PositiveIntegerToHanStr(String NumStr) { // 输入字符串必须正整数,只允许前导空格(必须右对齐),不宜有前导零 String RMBStr = ""; boolean lastzero = false; boolean hasvalue = false; // 亿、万进位前有数值标记 int len, n; len = NumStr.length(); if (len > 15) return "数值过大!"; for (int i = len - 1; i >= 0; i--) { if (NumStr.charAt(len - i - 1) == ' ') continue; n = NumStr.charAt(len - i - 1) - '0'; if (n < 0 || n > 9) return "输入含非数字字符!"; if (n != 0) { if (lastzero) RMBStr += HanDigiStr[0]; // 若干零后若跟非零值,只显示一个零 // 除了亿万前的零不带到后面 // if( !( n==1 && (i%4)==1 && (lastzero || i==len-1) ) ) // // 如十进位前有零也不发壹音用此行 //modify by xym 2009-11-03 //if (!(n == 1 && (i % 4) == 1 && i == len - 1)) // 十进位处于第一位不发壹音 RMBStr += HanDigiStr[n]; RMBStr += HanDiviStr[i]; // 非零值后加进位,个位为空 hasvalue = true; // 置万进位前有值标记 } else { if ((i % == 0 || ((i % == 4 && hasvalue)) // 亿万之间必须有非零值方显示万 RMBStr += HanDiviStr[i]; // “亿”或“万” } if (i % 8 == 0) hasvalue = false; // 万进位前有值标记逢亿复位 lastzero = (n == 0) && (i % 4 != 0); } if (RMBStr.length() == 0) return HanDigiStr[0]; // 输入空字符或"0",返回"零" return RMBStr; } } |
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发表时间:2011-09-03
请输入一个数字(精确到小数点后两位):
1000000001010 ¥:壹万零壹仟零壹拾圆整 在亿单位上前3为零的情况下 应该加上处理 |
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