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一个关于字串的排序算法~~

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作者 正文
   发表时间:2009-03-19  
有如下一些数据:
1-2-3-4-5
2-3-2
2-4-4-2
1-6
保存在一个文本文档中(ANSI编码格式)。要求排序成如下结果:

1-6
1-2-3-4-5
2-4-4-2
2-3-2

即以每一行的最后一个元素进行排序,如果相同再以之前一个排序。都是降序。。

有兴趣的可以试试。

package com.watersoft.file;

import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;

public class Sort {
	private int lineCount;
	private int numberCount;
	private String path;
	private int[][] matrix;

	/**
	 * *
	 * 
	 * @param args
	 *            contains the path of a text file which include the data being
	 *            sorted
	 */
	public static void main(String[] args) {
		if (args.length < 1) {
			System.err.println("Specific a file please!");
			return;
		}
		System.out.println(">>> Information: sort start ..\n");
		Sort s = new Sort();
		s.setPath(args[0]);
		s.doSort();
		s.display();
		System.out.println("\n>>> Information: sort end ..");
	}

	/** * do sort: initialize, parse, then sort. */
	public void doSort() {
		init();
		parse();
		for (int index = 0; index < this.lineCount - 1; index++)
			for (int innerIndex = 0; innerIndex < this.lineCount - 1; innerIndex++)
				sort(innerIndex, this.numberCount - 1);
	}

	/**
	 * * sort the given data according to the given row index and column index *
	 * 
	 * @param rowIndex
	 *            current row *
	 * @param colIndex
	 *            current column
	 */
	private void sort(int rowIndex, int colIndex) {
		int aInt = this.matrix[rowIndex][colIndex];
		int bInt = this.matrix[rowIndex + 1][colIndex];
		int temp = 0;
		if (aInt < bInt) { /* * swap two rows */
			for (int index = 0; index < this.numberCount; index++) {
				temp = this.matrix[rowIndex][index];
				this.matrix[rowIndex][index] = this.matrix[rowIndex + 1][index];
				this.matrix[rowIndex + 1][index] = temp;
			}
		} else if (aInt == bInt) { /* * compare previous elements of two rows */
			colIndex--;
			sort(rowIndex, colIndex);
		}
	}

	/**
	 * * read file to make sure the dimension of matrix *
	 * 
	 * @return boolean value, true if successfully done, else false
	 */
	private boolean init() {
		try {
			FileReader fr;
			fr = new FileReader(this.path);
			BufferedReader br = new BufferedReader(fr);
			String tempString;
			int lc = 0;
			int nc = 0;
			while ((tempString = br.readLine()) != null) {
				lc++;
				nc = (nc < tempString.split("-").length) ? tempString
						.split("-").length : nc;
			}
			this.lineCount = lc;
			this.numberCount = nc;
		} catch (FileNotFoundException e) {
			System.err.println("Error: cannot find file:[" + this.path + "]");
			return false;
		} catch (IOException e) {
			System.err.println("Error: cannot read file..");
			return false;
		}
		return true;
	}

	private boolean parse() { /* * initialize matrix */
		this.matrix = new int[this.lineCount][this.numberCount];
		for (int index = 0; index < this.lineCount; index++)
			for (int innerIndex = 0; innerIndex < this.numberCount; innerIndex++)
				this.matrix[index][innerIndex] = Integer.MAX_VALUE;
		try {
			FileReader fr;
			fr = new FileReader(this.path);
			BufferedReader br = new BufferedReader(fr);
			String tempString;
			String[] tempArray;
			int lc = 0;
			int baseIndex = 0;
			while ((tempString = br.readLine()) != null) {
				tempArray = tempString.split("-");
				baseIndex = this.numberCount - tempArray.length;
				for (int index = baseIndex; index < this.numberCount; index++)
					this.matrix[lc][index] = Integer.parseInt(tempArray[index
							- baseIndex]);
				lc++;
			}
		} catch (FileNotFoundException e) {
			System.err.println("Error: cannot find file:[" + this.path + "]");
			return false;
		} catch (IOException e) {
			System.err.println("Error: cannot read file..");
			return false;
		}
		return true;
	}

	/** * display sorted result */
	public void display() {
		for (int index = 0; index < this.lineCount; index++) {
			for (int innerIndex = 0; innerIndex < this.numberCount; innerIndex++) {
				if (this.matrix[index][innerIndex] != Integer.MAX_VALUE)
					if (innerIndex + 1 != this.numberCount)
						System.out.print(this.matrix[index][innerIndex] + "-");
					else
						System.out.print(this.matrix[index][innerIndex]);
			}
			System.out.println();
		}
	}

	public void setPath(String path) {
		this.path = path;
	}
}
   发表时间:2009-08-04   最后修改:2009-08-04
package test;

import java.io.BufferedReader;
import java.io.FileReader;
import java.util.ArrayList;
import java.util.Collections;
import java.util.Iterator;
import java.util.List;

public class StringSort {

	public static void main(String[] args){
		StringSort ss = new StringSort();
		//you'd better judge the null
		List<String> number = ss.sortString(ss.readString());
		ss.printResult(number);
	}
	
	
	//read string from file
	private List<String> readString(){
		List<String> initString = new ArrayList<String>();
		try {
			BufferedReader readFile = new BufferedReader(new FileReader("C://string.txt"));
			String tempstring;
			while(null != (tempstring = readFile.readLine())){
				initString.add(ConvertString(tempstring));
			}
			return initString;
		}catch (Exception e) {
			e.printStackTrace();
			return null;
		}
	}
	
	// reverse and delete '-' from string  
	private String ConvertString(String number){
		String[] tempSting = number.split("-");
		List<String> tempList = new ArrayList<String>();
		for(int i=tempSting.length-1;i>=0;i--){
			tempList.add(tempSting[i]);
		}
		return tempList.toString();
	}
	
	// sort the List
	private List<String> sortString(List<String> list){
		List<String> result = new ArrayList<String>();
		//sort
		Collections.sort(list);
		//reverse
		Collections.reverse(list);
		// result collection
		for(int i=0;i<list.size();i++){
			String temp = list.get(i).replaceAll("\\D", "");
			StringBuffer sb= new StringBuffer();
			for(int index = temp.length()-1; index>=0;index--){
				sb.append(temp.charAt(index));
				sb.append(0 == index ?"":"-");
			}
			result.add(sb.toString());
		}
		return result;
	}
	
	//print the result
	private void printResult(List<String> number){
		Iterator i = number.iterator();
		while(i.hasNext()){
			System.out.println(i.next());
		}
	}
}

 

1 请登录后投票
   发表时间:2009-09-04  
我觉得有一个最好的办法:
思路:1.先将每个字符串赋值给一个String;
、     2.讲String集体给byte[]
      4.根据byte的最后一个字符的值来比较;这样很方便;
0 请登录后投票
   发表时间:2009-12-15  
我想到一个方法不知道可以不?
把数字补齐,然后反方向变成long,比较大小,按照比较后的顺序把原文排序。
说明:
1-2-3-4-5
2-3-2
2-4-4-2
1-6
补齐:
1-2-3-4-5①
0-0-2-3-2②
0-2-4-4-2③
0-0-0-1-6④
反向变成long:
54321
23200
24420
61000
排序:
61000④
54321①
24420③
23200②
1 请登录后投票
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