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作者 | 正文 |
发表时间:2007-11-26
joined-subclass中的一个疑问?
假设有父类Card ,子类 Card_1,Card_2,Card_3 Code:为 [/list] public class Card { private Long id; private String card_name; //get/set方法省略 } public class Card_1 extends Card { private String card_1_filed;//get/set方法省略 } public class Card_2 extends Card { private String card_2_filed;//get/set方法省略 } public class Card_3 extends Card { private String card_3_filed;//get/set方法省略 } metadata mapping file : <hibernate-mapping package="hibernate.model" auto-import="false"> <class name="Card" table="superCard_join_2"> <id name="id" column="card_id"> <generator class="native" /> </id> <discriminator column="card_type" type="string"></discriminator> <property name="card_name" column="card_name" type="string" /> <subclass name="Card_1" discriminator-value="1"> <join table="Card_1_2" fetch="select"> <key column="card_id"></key> <property name="card_1_filed" type="string"></property> </join> </subclass> <subclass name="Card_2" discriminator-value="2"> <join table="Card_2_2" fetch="select"> <key column="card_id"></key> <property name="card_2_filed" type="string"></property> </join> </subclass> <subclass name="Card_3" discriminator-value="3"> <join table="Card_3_2" fetch="select"> <key column="card_id"></key> <property name="card_3_filed" type="string"></property> </join> </subclass> </class> </hibernate-mapping> [list=] 我做父类查询的时候生成的sql语句为: select card0_.card_id as card1_0_, card0_.card_name as card2_0_, card0_1_.card_1_filed as card2_1_, card0_2_.card_2_filed as card2_2_, card0_3_.card_3_filed as card2_3_, case when card0_1_.card_id is not null then 1 when card0_2_.card_id is not null then 2 when card0_3_.card_id is not null then 3 when card0_.card_id is not null then 0 end as clazz_ from superCard_join card0_ left outer join Card_1 card0_1_ on card0_.card_id=card0_1_.card_id left outer join Card_2 card0_2_ on card0_.card_id=card0_2_.card_id left outer join Card_3 card0_3_ on card0_.card_id=card0_3_.card_id 请问各位用什么方式才能将子类的left out join去掉呢? 声明:ITeye文章版权属于作者,受法律保护。没有作者书面许可不得转载。
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