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锁定老帖子 主题:[leetcode] PathSum
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发表时间:2014-10-25
/** * <pre> * Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum. * * For example: * Given the below binary tree and sum = 22, * 5 * / \ * 4 8 * / / \ * 11 13 4 * / \ \ * 7 2 1 * return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22. * </pre> * */ public class PathSum { public class TreeNode { int val; TreeNode left; TreeNode right; TreeNode(int x) { val = x; } } public class Solution { public boolean hasPathSum(TreeNode root, int sum) { if (root == null) return false; if (root.left == null && root.right == null) return root.val == sum; return hasPathSum(root.left, sum - root.val) || hasPathSum(root.right, sum - root.val); } } } 声明:ITeye文章版权属于作者,受法律保护。没有作者书面许可不得转载。
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