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发表时间：2013-09-11
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<div id="question_109" class="row-odd question-title" style="margin: 0px; padding: 5px 8px; border: 1px solid #f8f8f8; font-size: 13px; vertical-align: baseline; background-color: #f8f8f8; cursor: pointer; color: #222222; font-family: 'Helvetica Neue', arial, sans-serif;">
<strong style="margin: 0px; padding: 0px; border: 0px; vertical-align: baseline; background-color: transparent;">Convert Sorted List to Binary Search Tree</strong><span class="date" style="margin: 0px 10px 0px 0px; padding: 0px; border: 0px; font-size: 10px; vertical-align: baseline; background-color: transparent; color: #999999; float: right;" title="2012-10-03 00:35:00">Oct 3 '12</span><span class="stats" style="margin: 0px; padding: 1px 4px; border: 0px; font-size: 11px; vertical-align: baseline; background-color: #eeeeee; color: #999999; width: 65px; text-align: center;" title="5768 accepted submissions out of 16298 (35%)">5768 / 16298</span>
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<div class="row-odd question-content" style="margin: 0px; padding: 5px 8px 5px 55px; border: 1px solid #f8f8f8; font-size: 13px; vertical-align: baseline; background-color: #f8f8f8; color: #222222; font-family: 'Helvetica Neue', arial, sans-serif;">
<p style="margin-bottom: 20px; border: 0px; vertical-align: baseline; background-color: transparent;">Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.</p>
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<p> </p>
<p> </p>
<pre name="code" class="cpp">/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode *sortedListToBST(ListNode *head) {
if (head == NULL) return NULL;
ListNode* t = head;
int len = 0;
while (t != NULL) len++, t = t->next;
return gen(head, 0, len - 1);
}
TreeNode *gen(ListNode* &cur, int start, int end) {
if (start > end) return NULL;
int mid = start + (end -start) / 2;
TreeNode *left = gen(cur, start, mid - 1);
TreeNode *node = new TreeNode(cur->val);
cur = cur->next;
node->left = left;
node->right = gen(cur, mid+1, end);
}
};</pre>
<p> </p>
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