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[Leetcode] Combination Sum

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   发表时间:2013-08-20  
Combination SumMar 7 '125736 / 16047

Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.

The same repeated number may be chosen from C unlimited number of times.

Note:

  • All numbers (including target) will be positive integers.
  • Elements in a combination (a1a2, � , ak) must be in non-descending order. (ie, a1 ? a2 ? � ? ak).
  • The solution set must not contain duplicate combinations.

 

For example, given candidate set 2,3,6,7 and target 7
A solution set is: 
[7] 
[2, 2, 3] 

 

 

 

class Solution {
public:
    vector<vector<int> > res;
    int n;
    vector<vector<int> > combinationSum(vector<int> &candidates, int target) {
        vector<int> r;
        res.clear();
        n = candidates.size();
        sort(candidates.begin(), candidates.end());
        gen(r,0,0, candidates, target);
        return res;
    }
    
    void gen(vector<int> &r,int sum,int l, const vector<int>& can, int tar) {
        if (sum == tar) {
            res.push_back(r);
            return;
        }
        if (sum > tar) return ;
        
        for (int i = l; i < n; i++) {
            r.push_back(can[i]);
            sum += can[i];
            gen(r, sum,i, can, tar);
            sum -= can[i];
            r.pop_back();
        }
        
    }
};

 

 

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