Given n, generate all structurally unique BST's (binary search trees) that store values 1...n.
For example,
Given n = 3, your program should return all 5 unique BST's shown below.
1 3 3 2 1 \ / / / \ \ 3 2 1 1 3 2 / / \ \ 2 1 2 3
confused what "{1,#,2,3}"
means? > read more on how binary tree is serialized on OJ.
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: vector<TreeNode *> generateTrees(int n) { return getTrees(1, n); } vector<TreeNode*> getTrees(int start, int end) { vector<TreeNode* > res; if ( start > end ) { res.push_back(NULL); return res; } for (int i = start; i <= end; i++) { vector<TreeNode*> left = getTrees(start, i-1); vector<TreeNode*> right = getTrees(i+1, end); for (int l = 0; l < left.size(); l++) { for (int r = 0; r < right.size() ;r++) { TreeNode* cur = new TreeNode(i); cur->left = left[l]; cur->right = right[r]; res.push_back(cur); } } } } };