python抓取google搜索url

import sys
url = ('https://ajax.googleapis.com/ajax/services/search/web''?v=1.0&q=%s&rsz=8&start=%s') % (search,page)
try:
    request = urllib2.Request(
    url, None, {'Referer': 'http://www.baidu.com'})
    response = urllib2.urlopen(request)
            
# Process the JSON string.
    results = simplejson.load(response)
    info = results['responseData']['results']
except Exception,e:
    print e
    time.sleep(5)
    continue
            
    for minfo in info:
        for key in minfo.keys():
            if key == 'url':
                 try:
                     print 'url:%s' % minfo[key]

1. https://ajax.googleapis.com/ajax/services/search/web is an old service, the results are not quite as good as the google.com results, especially the ranking (order of the rsulting urls)
2. urllib2.urlopen has leaks, if you run this for a miilion time, your machine network is likely going down.

想多学习一门语言，所以最近也在看python，学习了。。。