dom4j解析xml文件的问题

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dom4j解析xml文件的问题10

需要解析的xml文件内容如下：
<xxx>
<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:SOAP-ENC="http://schemas.xmlsoap.org/soap/encoding/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:m0="http://group.unicom.com/xsd">
<SOAP-ENV:Body>
<m:syncAreaInfo xmlns:m="http://service.unicom.com">
<m:arg0>
<m0:operate_type>I</m0:operate_type>
<m0:area_code>001</m0:area_code>
<m0:area_name>String</m0:area_name>
<m0:area_frame>String</m0:area_frame>
<m0:order_no>0</m0:order_no>
<m0:parent_area_code>String</m0:parent_area_code>
<m0:start_date>String</m0:start_date>
<m0:end_date>String</m0:end_date>
<m0:area_level>0</m0:area_level>
<m0:validflag>String</m0:validflag>
<m0:remark>String</m0:remark>
<m0:para>String</m0:para>
<m0:para_id>String</m0:para_id>
<m0:para_value>String</m0:para_value>
</m:arg0>
</m:syncAreaInfo>
</SOAP-ENV:Body>
</SOAP-ENV:Envelope>

<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:SOAP-ENC="http://schemas.xmlsoap.org/soap/encoding/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:m0="http://group.unicom.com/xsd">
<SOAP-ENV:Body>
<m:syncAreaInfo xmlns:m="http://service.unicom.com">
<m:arg0>
<m0:operate_type>D</m0:operate_type>
<m0:area_code>001</m0:area_code>
<m0:area_name>String</m0:area_name>
<m0:area_frame>String</m0:area_frame>
<m0:order_no>0</m0:order_no>
<m0:parent_area_code>String</m0:parent_area_code>
<m0:start_date>String</m0:start_date>
<m0:end_date>String</m0:end_date>
<m0:area_level>0</m0:area_level>
<m0:validflag>String</m0:validflag>
<m0:remark>String</m0:remark>
<m0:para>String</m0:para>
<m0:para_id>String</m0:para_id>
<m0:para_value>String</m0:para_value>
</m:arg0>
</m:syncAreaInfo>
</SOAP-ENV:Body>
</SOAP-ENV:Envelope>
</xxx>

我要取到所有的<SOAP-ENV:Body>元素
java 代码如下：
public static void main(String[] args) {
SAXReader saxReader = new SAXReader();
try {
Document document = saxReader.read("D:/syncAreaInfo.xml");
List list=document.selectNodes("//m:arg0");
Iterator iterator=list.iterator();
while(iterator.hasNext()){
Element node=(Element)iterator.next();
System.out.println("node is "+node.getName());
}
} catch (DocumentException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
但是貌似标签命中包含“：”就会出错
org.dom4j.XPathException: Exception occurred evaluting XPath: //m:arg0. Exception: XPath expression uses unbound namespace prefix m
at org.dom4j.xpath.DefaultXPath.handleJaxenException(DefaultXPath.java:374)
at org.dom4j.xpath.DefaultXPath.selectNodes(DefaultXPath.java:134)
at org.dom4j.tree.AbstractNode.selectNodes(AbstractNode.java:166)
at com.unicom.service.XmlParser.main(XmlParser.java:20)
Exception in thread "main"

如果把“：”换成“-”就没有问题，但这个文件时别人传过来的，格式就是这样又不能改，请问怎样才能取到这些节点呢

Java综合

2011年8月11日 17:46

duruilin
3
0 0 2

3个答案按时间排序按投票排序

0 0

采纳的答案

XML中，ooo:xxx中，ooo是命名空间。

XML里有xmlns:m="http://service.unicom.com"这样的声明，但是Java程序里没有。所以，处理带命名空间的XML的时候，应该告诉Java程序，每个命名空间前缀（比如“m”）具体代表什么命名空间，（比如“http://service.unicom.com”）。

package dom4jnstest;

import java.util.Collections;
import java.util.Iterator;
import java.util.List;

import org.dom4j.Document;
import org.dom4j.Element;
import org.dom4j.io.SAXReader;
import org.dom4j.xpath.DefaultXPath;

public class Dom4jNsTest {

	public static void main(String[] args) throws Exception {
		SAXReader saxReader = new SAXReader();
		Document document = saxReader.read(Dom4jNsTest.class
				.getResourceAsStream("x.xml"));

		DefaultXPath xpath = new DefaultXPath("//m:arg0");
		xpath.setNamespaceURIs(Collections.singletonMap("m",
				"http://service.unicom.com"));

		List list = xpath.selectNodes(document);
		Iterator iterator = list.iterator();
		while (iterator.hasNext()) {
			Element node = (Element) iterator.next();
			System.out.println("node is " + node.getName());
		}
	}
}

2011年8月11日 18:05