本月博客排行
-
第1名
kaizi1992 -
第2名
arpenker -
第3名
wy_19921005 - hanbaohong
- jh108020
年度博客排行
-
第1名
龙儿筝 -
第2名
宏天软件 -
第3名
青否云后端云 - vipbooks
- wy_19921005
- benladeng5225
- fantaxy025025
- e_e
- kaizi1992
- tanling8334
- arpenker
- sam123456gz
- javashop
- zysnba
- xiangjie88
- lemonhandsome
- wallimn
- ganxueyun
- Xeden
- xyuma
- zhanjia
- wangchen.ily
- jh108020
- johnsmith9th
- zxq_2017
- jbosscn
- forestqqqq
- daizj
- ajinn
- xpenxpen
- 喧嚣求静
- ranbuijj
- kingwell.leng
- silverend
- kristy_yy
- lchb139128
- jveqi
- lich0079
- lzyfn123
- java-007
- sunj
- yeluowuhen
- lerf
- xiaoxinye
- flashsing123
- lxguy
- zhangjijun
- bosschen
- lyndon.lin
- sunnylocus
最新文章列表
Display back button on action bar and back event
原文地址:
https://stackoverflow.com/a/37185334
I think onSupportNavigateUp() is best and Easiest way to do so
check the code below
if you want it programmatically Add this line in onCreate() method
getSup ...
Android 点击back键两次退出程序
Android中为了界面上的简洁,可以通过点击两次back键退出程序,而不用退出按钮。ok,直接上代码
private long exitTime = 0;
@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
ExitApp();
return false;
}
public ...
Android按back键退到后台
public boolean onKeyDown(int keyCode, KeyEvent event) {
if(keyCode == 4){
moveTaskToBack(true);
}
return super.onKeyDown(keyCode, event);
}
即可
方法2:
Android应用开发中, 有一种场景,就是我们不希望用户直接按Back键退 ...
再按一次后退键退出应用程序
long lastTouchBackTime = 0L;
long nowTime = 0L;
@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
if (keyCode == KeyEvent.KEYCODE_BACK) {
nowTime = System.currentTimeMillis();
...