不用判断语句求俩数中的大（或者小）数

private static int Max(int a, int b)
    {
      int[] s = new int[] { a, b };
      int c = a-b;
      int index = (c >> 31) & 0x0001;  

      return s[index];    
    }

int max = a - ((a - b) & ((a - b) >> 31));

int a；
a^a==0 //true
a^0==a //true
a==a^a^a  //这个很有趣

public class MaxMin {
	static int max = 0 ;
	public static void main(String[] args) throws InterruptedException {
		MaxMin m = new MaxMin();
		int a = m.max(9, 10);
		System.out.println("最大:"+a);
		
	}
	public int max(int a , int b ) throws InterruptedException{
		new MyThread(a,this).start();
		new MyThread(b,this).start();
		Thread.sleep((a+b));	
		return this.max;
	}
}

class MyThread extends Thread{
	public int f = 0;
	public MaxMin max ;
	MyThread(int f , MaxMin max){
		this.f=f;
		this.max = max;
	}
	public void run() {
		try {sleep(f);} catch (Exception e) {}
		max.max = f;
	}
}

public static int getMaxValueWidthoutBoolean(int a,int b){
 int[] array=new int[a];
try{
//只要b比a大，数组越界，肯定会导致异常，否则b比a小
//所以在catch模块中返回b，非异常返回a即可
array[b]=0;
}catch(Exception ex){
return b;
}
return a;
}

适合负数吗？