一个正则表达式的问题.

		
		String needToMatch = "<table><tr>fadsf</tr><tr>dafqewrdf</tr></table>";

		
		Pattern p = Pattern.compile("\\Q<tr>\\E.*\\Q</tr>\\E");
		Matcher matcher = p.matcher(needToMatch);
		while(matcher.find()){
            System.out.println("I found the text \"" + matcher.group() +
                    "\" starting at index " + matcher.start() +
                    " and ending at index " + matcher.end() + ".");
		}

得到的是
I found the text "<tr>fadsf</tr><tr>dafqewrdf</tr>" starting at index 7 and ending at index 39.

其实我想解析成<tr>fadsf</tr> 和 <tr>dafqewrdf</tr>

请问这个正则表达式该怎么写呢? thanks

又见贪婪

Pattern p = Pattern.compile("\\Q<tr>\\E.*?\\Q</tr>\\E");; 

其实还是jakarta 的oro模块好用,更符合perl的习惯

sun实现的正则表达式不伦不类的,当然还是能用的

谢谢, 看了sun网站上的java tutorial的正则表达式这张. 对这节不是很清楚
http://java.sun.com/docs/books/tutorial/extra/regex/quant.html


Current REGEX is: .*foo  // greedy quantifier
Current INPUT is: xfooxxxxxxfoo
I found the text "xfooxxxxxxfoo" starting at index 0 and ending at index 13.

Current REGEX is: .*?foo  // reluctant quantifier
Current INPUT is: xfooxxxxxxfoo
I found the text "xfoo" starting at index 0 and ending at index 4.
I found the text "xxxxxxfoo" starting at index 4 and ending at index 13.

Current REGEX is: .*+foo // possessive quantifier
Current INPUT is: xfooxxxxxxfoo
No match found.

茅塞顿开!

推荐一个写正则的插件QuickRex：

http://prdownloads.sourceforge.net/easyeclipse/eclipseplugin-quickrex-2.0.0.tar.gz

请教一下，那个\Q和\E有什么用？

避免context中有特殊意义的字符, * { () ....

你在用greedy mode,用lazy mode就解决问题啦
jakarta ORO 的使用方法: &lt;tr&gt;.*?&lt;/tr&gt;
hoho,前两天刚看了
sams.teach.yourself.regular.expressions.in.10.minutes

\\Q&lt;tr&gt;\\E.*?\\Q&lt;/tr&gt;\\E

没感觉有啥作用。。。能详细解释一下吗？

String s = "abc*def*ghj";
试试System.out.println(s.split("*"));

怎么能这么写呢？应该是System.out.println(s.split("\\*"));吧