解决Hibernate3.0的Date类型的数据返回结果没有时分秒的问题

//$Id: DateType.java 8891 2005-12-21 05:13:29Z oneovthafew $
package org.hibernate.type;

import java.sql.Date;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.sql.Timestamp;
import java.sql.Types;
import java.text.DateFormat;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Calendar;

import org.hibernate.EntityMode;
import org.hibernate.Hibernate;
import org.hibernate.HibernateException;
import org.hibernate.dialect.Dialect;

/**
 * <tt>date</tt>: A type that maps an SQL DATE to a Java Date.
 * @author Gavin King
 * @modify by zhenjw 
 */
public class DateType extends MutableType implements IdentifierType, LiteralType {

	private static final String DATE_FORMAT = "dd MMMM yyyy";

	public Object get(ResultSet rs, String name) throws SQLException {		
		//return rs.getDate(name);		
		Timestamp tamp=rs.getTimestamp(name);
		Date result=null;
		if(tamp!=null)
			result=new Date(tamp.getTime());		
		return result;
		
	}

	public Class getReturnedClass() {
		return java.util.Date.class;
	}

	public void set(PreparedStatement st, Object value, int index) throws SQLException {

		Date sqlDate;
		if ( value instanceof Date) {
			sqlDate = (Date) value;
		}
		else {
			sqlDate = new Date( ( (java.util.Date) value ).getTime() );
		}
		st.setDate(index, sqlDate);
	}

	public int sqlType() {
		return Types.DATE;
	}

	public boolean isEqual(Object x, Object y) {

		if (x==y) return true;
		if (x==null || y==null) return false;

		java.util.Date xdate = (java.util.Date) x;
		java.util.Date ydate = (java.util.Date) y;
		
		if ( xdate.getTime()==ydate.getTime() ) return true;
		
		Calendar calendar1 = java.util.Calendar.getInstance();
		Calendar calendar2 = java.util.Calendar.getInstance();
		calendar1.setTime( xdate );
		calendar2.setTime( ydate );

		return Hibernate.CALENDAR_DATE.isEqual(calendar1, calendar2);
	}

	public int getHashCode(Object x, EntityMode entityMode) {
		Calendar calendar = java.util.Calendar.getInstance();
		calendar.setTime( (java.util.Date) x );
		return Hibernate.CALENDAR_DATE.getHashCode(calendar, entityMode);
	}
	
	public String getName() { return "date"; }

	public String toString(Object val) {
		return new SimpleDateFormat(DATE_FORMAT).format( (java.util.Date) val );
	}

	public Object deepCopyNotNull(Object value) {
		return new Date( ( (java.util.Date) value ).getTime() );
	}

	public Object stringToObject(String xml) throws Exception {
		return DateFormat.getDateInstance().parse(xml);
	}

	public String objectToSQLString(Object value, Dialect dialect) throws Exception {
		return '\'' + new Date( ( (java.util.Date) value ).getTime() ).toString() + '\'';
	}

	public Object fromStringValue(String xml) throws HibernateException {
		try {
			return new SimpleDateFormat(DATE_FORMAT).parse(xml);
		}
		catch (ParseException pe) {
			throw new HibernateException("could not parse XML", pe);
		}
	}
	
}