python编程的纠结

场景：

1. 定义一个对象

class Strategy:
  """
  Attributes:
   - version
   - inteval
   - period
   - validDay
   - onNetBeg
   - circleType
  """

  thrift_spec = (
    None, # 0
    (1, TType.STRING, 'version', None, None, ), # 1
    (2, TType.STRING, 'inteval', None, None, ), # 2
    (3, TType.STRING, 'period', None, None, ), # 3
    (4, TType.STRING, 'validDay', None, None, ), # 4
    (5, TType.STRING, 'onNetBeg', None, None, ), # 5
    (6, TType.I32, 'circleType', None,     1, ), # 6
  )

  def __init__(self, version=None, inteval=None, period=None, validDay=None, onNetBeg=None, circleType=thrift_spec[6][4],):
    self.version = version
    self.inteval = inteval
    self.period = period
    self.validDay = validDay
    self.onNetBeg = onNetBeg
    self.circleType = circleType

  def read(self, iprot):
    if iprot.__class__ == TBinaryProtocol.TBinaryProtocolAccelerated and isinstance(iprot.trans, TTransport.CReadableTransport) and self.thrift_spec is not None and fastbinary is not None:
      fastbinary.decode_binary(self, iprot.trans, (self.__class__, self.thrift_spec))
      return
    iprot.readStructBegin()
    while True:
      (fname, ftype, fid) = iprot.readFieldBegin()
      if ftype == TType.STOP:
        break
      if fid == 1:
        if ftype == TType.STRING:
          self.version = iprot.readString();
        else:
          iprot.skip(ftype)
      elif fid == 2:
        if ftype == TType.STRING:
          self.inteval = iprot.readString();
        else:
          iprot.skip(ftype)
      elif fid == 3:
        if ftype == TType.STRING:
          self.period = iprot.readString();
        else:
          iprot.skip(ftype)
      elif fid == 4:
        if ftype == TType.STRING:
          self.validDay = iprot.readString();
        else:
          iprot.skip(ftype)
      elif fid == 5:
        if ftype == TType.STRING:
          self.onNetBeg = iprot.readString();
        else:
          iprot.skip(ftype)
      elif fid == 6:
        if ftype == TType.I32:
          self.circleType = iprot.readI32();
        else:
          iprot.skip(ftype)
      else:
        iprot.skip(ftype)
      iprot.readFieldEnd()
    iprot.readStructEnd()

  def write(self, oprot):
    if oprot.__class__ == TBinaryProtocol.TBinaryProtocolAccelerated and self.thrift_spec is not None and fastbinary is not None:
      oprot.trans.write(fastbinary.encode_binary(self, (self.__class__, self.thrift_spec)))
      return
    oprot.writeStructBegin('CircleStrategy')
    if self.version is not None:
      oprot.writeFieldBegin('version', TType.STRING, 1)
      oprot.writeString(self.version)
      oprot.writeFieldEnd()
    if self.inteval is not None:
      oprot.writeFieldBegin('inteval', TType.STRING, 2)
      oprot.writeString(self.inteval)
      oprot.writeFieldEnd()
    if self.period is not None:
      oprot.writeFieldBegin('period', TType.STRING, 3)
      oprot.writeString(self.period)
      oprot.writeFieldEnd()
    if self.validDay is not None:
      oprot.writeFieldBegin('validDay', TType.STRING, 4)
      oprot.writeString(self.validDay)
      oprot.writeFieldEnd()
    if self.onNetBeg is not None:
      oprot.writeFieldBegin('onNetBeg', TType.STRING, 5)
      oprot.writeString(self.onNetBeg)
      oprot.writeFieldEnd()
    if self.circleType is not None:
      oprot.writeFieldBegin('circleType', TType.I32, 6)
      oprot.writeI32(self.circleType)
      oprot.writeFieldEnd()
    oprot.writeFieldStop()
    oprot.writeStructEnd()

  def validate(self):
    return


  def __repr__(self):
    L = ['%s=%r' % (key, value)
      for key, value in self.__dict__.iteritems()]
    return '%s(%s)' % (self.__class__.__name__, ', '.join(L))

  def __eq__(self, other):
    return isinstance(other, self.__class__) and self.__dict__ == other.__dict__

  def __ne__(self, other):
    return not (self == other)

 2. 当实例化对象时

strategy = Strategy()
strategy.interval = str(a.timeInterval)

   

3. 取值发现

strategy.inteval 取不到！

 

4. 纠结是

赋值的属性是strategy.interval 

原来是对象定义是属性名称写错了。

但是python语义是不会报错，只会给对象多增加一个属性！

 

5.解决办法

1.细心

2.再细心

3.还有就是带着放大镜找问题！