寻求N*N方格对角到对角的走法总和

1:
def matrix(m,n):
    if m == 1:
       return n+1
    if n == 1:
       return m+1
    else:
       return matrix(m,n-1)+matrix(m-1,n)

02:
def getWayNum(n):
    def do(l):
        rel=[]
        length=len(l)
        for i in range(length+1):
            if i==length-1:
                rel.append(l[i])
            elif i==length:
                rel.append((reduce(lambda x,y:x+y,rel))*2)
            else:
                rel.append((reduce(lambda x,y:x+y,l[:i+1])))
        return rel
    l=[1]
    for i in range(1,n+1):
        l=do(l)
    return l[n]

def waynum(n):
    listy=[i for i in xrange(1,n+2)]
    for i in xrange(1,n):
        for j in xrange(1,n+1):
            listy[j]=listy[j-1]+listy[j]
    print listy[n]