在ORACLE大数据量下的分页解决方法

在ORACLE大数据量下的分页解决方法。

一般用截取ID方法，还有是三层嵌套方法。

<% 

int i=1; 

int numPages=14; 

String pages = request.getParameter("page") ; 

int currentPage = 1; 

currentPage=(pages==null)?(1):{Integer.parseInt(pages)} 

sql = "select count(*) from tables"; 

ResultSet rs = DBLink.executeQuery(sql) ; 

while(rs.next()) i = rs.getInt(1) ; 

int intPageCount=1; 

intPageCount=(i%numPages==0)?(i/numPages):(i/numPages+1); 

int nextPage ; 

int upPage; 

nextPage = currentPage+1; 

if (nextPage>=intPageCount) nextPage=intPageCount; 

upPage = currentPage-1; 

if (upPage<=1) upPage=1; 

rs.close(); 

sql="select * from tables"; 

rs=DBLink.executeQuery(sql); 

i=0; 

while((i<numPages*(currentPage-1))&&rs.next()){i++;} 

%> 

//输出内容 

//输出翻页连接 

合计:<%=currentPage%>/<%=intPageCount%><a href="List.jsp?page=1">第一页</a><a 



href="List.jsp?page=<%=upPage%>">上一页</a> 

<% 

for(int j=1;j<=intPageCount;j++){ 

if(currentPage!=j){ 

%> 

<a href="list.jsp?page=<%=j%>">[<%=j%>]</a> 

<% 

}else{ 

out.println(j); 

} 

} 

%> 

<a href="List.jsp?page=<%=nextPage%>">下一页</a><a href="List.jsp?page=<%=intPageCount%>">最后页 

</a>