查找不连续数字字符串

对己经排好序的数字字符串,查找出不连续的。

public class Test {

    /**
     * @param args
     */
    public static void main(String[] args) {

        String num = "3,6,7,8,9,10,11,12,14";
        int mid = 0;
        String[] zh = num.split(",");
        
        if (Integer.parseInt(zh[0]) != 1) {
            for (int n = 1; n < Integer.parseInt(zh[0]); n++) {
                System.out.println("----" + n);
            }
        }

        for (int i = 0; i < zh.length - 1; i++) {

            if (Integer.parseInt(zh[i + 1]) - Integer.parseInt(zh[i]) != 1) {
                for (int j = 1; j < Integer.parseInt(zh[i + 1]) - Integer.parseInt(zh[i]); j++) {
                    mid = Integer.parseInt(zh[i]) + j;
                    System.out.println("----" + mid);
                }
            }

        }
    }
}