Given an input array of number {1,2,3,4,5,6}, output number of array {2*3*4*5*6, 1*3*4*5*6,1*2*4*5*6,1*2*3*5*6,1*2*3*4*6,1*2*3*4*5 }. Do not use divide.
Solution:
public int[] getAllProductsExceptSelf(int[] num) { if(num == null || num.length == 1) return null; final int len = num.length; int[] result = new int[len]; int[] leftProducts = new int[len+1]; int[] rightProducts = new int[len+1]; leftProducts[0] = 1; rightProducts[len] = 1; for(int i=1; i<=len; i++) { leftProducts[i] = leftProducts[i-1] * num[i-1]; } for(int i=len-1; i>=0; i--) { rightProducts[i] = rightProducts[i+1] * num[i]; result[i] = leftProducts[i] * rightProducts[i+1]; } return result; }
Time Complexity: O(n).
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