ACM:1.2.8 Identity Card C语言版的解题方案

C语言版的，望诸位努力：

 

#include"stdio.h"
#include"string.h"
char *substr(const char *str,int n,int m,char p[]){
	char *cour;
	int i,j=0;
	cour=str;
	if(m>=n&&n>=0){
		for(i=0;i<m;i++){
			if(i>=n){
				p[j]=*cour;
				j++;
			}
			cour++;
		}
		p[j]='\0';
		cour=p;
		return cour;
	}
	else{
		return 0;
	}
}
int main(){
	char identity[20];
	char pr[5],mon[5],day[5],year[7];
	char *loc;
	int i;
	scanf("%d",&i);
	while(i--){
		scanf("%s",identity);
		substr(identity,0,2,pr);
		substr(identity,10,12,mon);
		substr(identity,12,14,day);
		substr(identity,6,10,year);
		switch(atoi(pr)){
			case 33:loc="Zhejiang";break;
			case 11:loc="Beijing";break;
			case 71:loc="Taiwan";break;
			case 81:loc="Hong Kong";break;
			case 82:loc="Macao";break;
			case 54:loc="Tibet";break;
			case 21:loc="Liaoning";break;
			case 31:loc="Shanghai";break;
			default:break;
		}
		printf("He/She is from %s,and his/her birthday is on %s,%s,%s based on the table.\n",loc,mon,day,year);	
	}
}