贴些编程题

1. 给定多项式A(x0)=anxn+an-1xn-1+…+a1x1+a0x0，求在x0处的值，可用Horner规则。
A(x0)=((anx0+an-1)x0+…+a1)x0+a0)

import java.io.*;
import java.util.*;
public class Polynomial {
	public static void main(String args[]){
		double a[]={2,-1,-3,5};
		double result = a[0];
		System.out.println("Please input the number of coefficient\n");
		Scanner in =new Scanner(System.in);
		int x = in.nextInt();
		for(int i=0;i<a.length-1;i++){
			result=result*x+a[i+1];
		}
		System.out.println("The Result is:"+result);
	}
}

2. 给定n个布尔变量x1,…,xn，输出所有可能的真值组合；

import java.io.*;
import java.util.*;
public class BoolCombination {
	public static void main(String args[]){
		int n;
		System.out.println("Input the number of the bool value\n");
		Scanner in = new Scanner(System.in);
		n = in.nextInt();
		System.out.println(PrintResult(n));
	}
	public static String PrintResult(int n){
		String re1="";
		String re2="";
		
		if(n==1)	
		{
			return("(true),(false)");
		}
		else 
		{
			re1=PrintResult(n-1).replace("(", "(true,");
			re2=PrintResult(n-1).replace("(", "(false,");
			return re1+","+re2;
		}
	}
}