Android如何发送Get请求

*URL可以随意改*/
        String uriAPI = "http://192.168.1.100:8080/test/test.jsp?u=wangyi&p=456"; 
        /*建立HTTP Get对象*/
        HttpGet httpRequest = new HttpGet(uriAPI); 
        try 
        { 
          /*发送请求并等待响应*/
          HttpResponse httpResponse = new DefaultHttpClient().execute(httpRequest); 
          /*若状态码为200 ok*/
          if(httpResponse.getStatusLine().getStatusCode() == 200)  
          { 
            /*读*/
            String strResult = EntityUtils.toString(httpResponse.getEntity());
            /*去没有用的字符*/
            strResult = eregi_replace("(\r\n|\r|\n|\n\r)","",strResult);
            mTextView1.setText(strResult); 
          } 
          else 
          { 
            mTextView1.setText("Error Response: "+httpResponse.getStatusLine().toString()); 
          } 
        } 
        catch (ClientProtocolException e) 
        {  
          mTextView1.setText(e.getMessage().toString()); 
          e.printStackTrace(); 
        } 
        catch (IOException e) 
        {  
          mTextView1.setText(e.getMessage().toString()); 
          e.printStackTrace(); 
        } 
        catch (Exception e) 
        {  
          mTextView1.setText(e.getMessage().toString()); 
          e.printStackTrace();  
        }