Java构造时成员初始化的陷阱

http://www.ehelper.com.cn/blog/post/40.html

public class A
{
	public A()
	{
		System.out.println("This is A()");
		this.Say();
	}

	public void Say()
	{
		System.out.println("This is A.Say()");
	}
}

public class B extends A
{
	public String name = "111";

	public B()
	{
		System.out.println("This is B()\t" + "name is " + name);
		name = "333";
	}

	public void Say() // 重载
	{
		name = "222";
		System.out.println("This is B.Say()\t" + "name is " + name);
	}

	public static void main(String[] args)
	{
		B oo = new B();
		System.out.println("This is main()\t" + "name is " + oo.name);
	}
}

This is A()
This is B.Say()	name is 222
This is B()	name is 111
This is main()	name is 333

一、类A的构造方法；
二、类A中执行的Say()是类B的，因为类B覆盖了类A的Say()，类A自己的Say()没有了；
三、类B的构造方法，看来之前执行了name = "111"。