oracle 树形结构

--第一题
select substr(sys_connect_by_path(t.dwdm, '->'), 3) 树形路径,
       t.dwdm 本级节点号,
       substr(sys_connect_by_path(t.dwbzmc, '->'), 3) 树形节点明朝,
       t.dwbzmc 本级节点名称
  from (select a.dwdm,
               a.dwbzmc,
               (case
                 when a.dwdm = a.ssdwbm then
                  null
                 else
                  a.ssdwbm
               end) ssdwbm,
               a.dwcc
          from test1 a) t
connect by prior t.dwdm = t.ssdwbm
 start with t.dwdm = '000000'
 order by t.dwdm


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--第2题

select a.occur_date,a.flag,sum(b.bonus_amt) from test a,test b 
where a.occur_date>=20030801 
and b.occur_date<=a.occur_date 
and a.flag=b.flag  
group by a.occur_date,a.flag;