Struts2+Spring整合

xiangxingchina

浏览: 523512 次
性别:
来自: 北京

最近访客更多访客>>

WoKo_Jb

lanmubai

forfelicity

linktoyl22

博主相关

博客

微博

相册

留言

关于我

文章分类

社区版块

存档分类

博客分类：

struts2

Spring Struts Bean JSP XML

Struts2和Spring整合,创建一个OA工程
1、整合struts2
1)导入strut2的jar包:commons-logging-1.0.4.jar,freemarker-2.3.8.jar,ognl- 2.6.11.jar,struts2-core-2.0.12.jar,xwork-2.06.jar。暂时导入这些jar包，到时候需要再倒入。
2)将struts.xml文件放置在OA工程的src目录下。
3)在web.xml里面配置struts2用到的核心过滤器。

Xml代码

< filter >
< filter-name > struts2 </ filter-name >
< filter-class > org.apache.struts2.dispatcher.FilterDispatcher </ filter-class >
</ filter >
< filter-mapping >
< filter-name > struts2 </ filter-name >
< url-pattern > /* </ url-pattern >
</ filter-mapping >

	<filter>
	    <filter-name>struts2</filter-name>
	    <filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>
	</filter>
	<filter-mapping>
	    <filter-name>struts2</filter-name>
	    <url-pattern>/*</url-pattern>
	</filter-mapping>

2、整合spring
1)导入spring的jar包:spring.jar
2)将applicationContext.xml文件放置在OA工程的WEB-INF目录下。
3)在web.xml里面配置spring用到的监听器。

Xml代码

< listener >
< listener-class > org.springframework.web.context.ContextLoaderListener </ listener-class >
</ listener >

<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

4)添加struts2-spring整合的插件:struts2-spring-plugin-2.0.12.jar,如果不使用这个插件，则需要在struts.xml里面配置:

Xml代码

< constant name = "struts.objectFactory" value = "org.apache.struts2.spring.StrutsSpringObjectFactory" />

<constant name="struts.objectFactory" value="org.apache.struts2.spring.StrutsSpringObjectFactory" />

3、测试struts2和spring整合对不对?
写一个jsp页面login.jsp来测试:

Html代码

< %@ page language = "java" contentType = "text/html; charset=UTF-8" pageEncoding = "UTF-8" % >
< %@ taglib prefix = "s" uri = "/struts-tags" % >
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
< html >
< head >
< meta http-equiv = "Content-Type" content = "text/html; charset=UTF-8" >
< title > Insert title here </ title >
</ head >
< body >
< s:form action = "Login" method = "post" >
< s:textfield name = "userName" label = "userName" > </ s:textfield >
< s:password name = "password" label = "password" > </ s:password >
< s:submit label = "submit" > </ s:submit >
</ s:form >
</ body >
</ html >

<%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%>
<%@ taglib prefix="s" uri="/struts-tags" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Insert title here</title>
</head>
<body>
    <s:form action="Login" method="post">
        <s:textfield name="userName" label="userName"></s:textfield>
        <s:password name="password" label="password"></s:password>
        <s:submit label="submit"></s:submit>
    </s:form>
</body>
</html>

写一个LoginAction

Java代码

package com.struts2.action;
import com.opensymphony.xwork2.ActionSupport;
import com.struts2.service.LoginService;
public class LoginAction extends ActionSupport {
private LoginService loginService;
private String userName;
private String password;
public void setLoginService(LoginService loginService) {
this .loginService = loginService;
}
public String getUserName() {
return userName;
}
public void setUserName(String userName) {
this .userName = userName;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this .password = password;
}
@Override
public String execute() throws Exception {
if (loginService.isLogin(userName, password))
return SUCCESS;
else
return INPUT;
}
}

package com.struts2.action;

import com.opensymphony.xwork2.ActionSupport;
import com.struts2.service.LoginService;
public class LoginAction extends ActionSupport {
	private LoginService loginService;
	private String userName;
	private String password;
	public void setLoginService(LoginService loginService) {
		this.loginService = loginService;
	}
	public String getUserName() {
		return userName;
	}
	public void setUserName(String userName) {
		this.userName = userName;
	}
	public String getPassword() {
		return password;
	}
	public void setPassword(String password) {
		this.password = password;
	}
	@Override
	public String execute() throws Exception {
		if(loginService.isLogin(userName, password))
			return SUCCESS;
		else
			return INPUT;
	}
}

写一个Service

Java代码

package com.struts2.service;
public interface LoginService {
boolean isLogin(String userName,String password);
}

package com.struts2.service;

public interface LoginService {
	boolean isLogin(String userName,String password);
}

写一个Service的实现

Java代码

package com.struts2.service.impl;
import com.struts2.service.LoginService;
public class LoginServiceImpl implements LoginService {
public boolean isLogin(String userName, String password) {
if ( "hello" .equals(userName) && "world" .equals(password))
return true ;
else
return false ;
}
}

package com.struts2.service.impl;

import com.struts2.service.LoginService;
public class LoginServiceImpl implements LoginService {

	public boolean isLogin(String userName, String password) {
		if("hello".equals(userName) && "world".equals(password))
			return true;
		else 
			return false;
	}
}

在struts.xml里面配置:

Xml代码

< package name = "struts2" extends = "struts-default" >
< action name = "Login" class = "loginAction" >
< result name = "success" > /result.jsp </ result >
< result name = "input" > /login.jsp </ result >
</ action >
</ package >

    <package name="struts2" extends="struts-default">
        <action name="Login" class="loginAction">
            <result name="success">/result.jsp</result>
            <result name="input">/login.jsp</result>
        </action>
    </package>

在applicationContext.xml里面配置:

Xml代码

< bean id = "loginService" class = "com.struts2.service.impl.LoginServiceImpl" > </ bean >
< bean id = "loginAction" class = "com.struts2.action.LoginAction" scope = "prototype" >
< property name = "loginService" ref = "loginService" > </ property >
</ bean >

    <bean id="loginService" class="com.struts2.service.impl.LoginServiceImpl"></bean>
    <bean id="loginAction" class="com.struts2.action.LoginAction" scope="prototype">
        <property name="loginService" ref="loginService"></property>
    </bean>

启动tomcat，分别输入hello和world，提交,结果为hello和world。说明struts2和spring整合成功。

分享到：

Struts2+Spring+Hibernate整合(续Struts2+ ... | HOSTS设置

2010-12-07 19:52
浏览 855
评论(0)
分类:编程语言
查看更多

发表评论

您还没有登录,请您登录后再发表评论

最近访客更多访客>>

博主相关

文章分类

社区版块

存档分类

最新评论