hibernate4.3.5 单向一对多 的诡异行为

版本：hibernate4.3.5
单向一对多，一端为主控端。一个person实体有多个address实体.采用主外键的方式。
person表有person_id,name,age三个cloumn,其中为PK。
address表有address_id,address_name,person_id，其中address_id为PK,person_id为FK，且为notNull。
person实体的定义：

@Id
@Column(name="PERSON_ID")
private int personId = 0;

@Column(name="NAME")
private String name = null;

@Column(name="AGE")
private int age = 0;
	
@OneToMany(targetEntity=Address_OneToMany.class)
@JoinColumn(name="PERSON_ID",nullable=false, referencedColumnName="PERSON_ID")
@Cascade(CascadeType.ALL)
private Set<Address_OneToMany> address = new HashSet<Address_OneToMany>();
省略setter,getter

address实体定义：

@Id 
@Column(name="ADDRESS_ID")
private int addressId=0;
	
@Column(name="ADDRESS_NAME")
private String addressName = null;
省略setter,getter

在client端，new两个address，再加到person的set中，最后persist这个person：

Address address1 = new Address(411,"lv shun");
		
Address address2 = new Address(101,"beijing");
		
Person person1 = new Person(210824,"father",59);
		
person1.getAddress().add(address1);
person1.getAddress().add(address2);
		
session.persist(person1);

按书上的说法，这种情况下，如果address表的外键person_id为notnull,则直接出错；如果address表的外键person_id可以为null，则先insert,再update。
但是我现在的情况是address表的外键person_id为notnull，但是却没有出错，而是先insert后update。而且insert时，person_id直接就可以取到personId,接着再用相同的值再update一次。如下：

insert 
    into
        TEST_PERSON
        (AGE, NAME, PERSON_ID) 
    values
        (?, ?, ?)
2014-12-19 14:18:29,378 TRACE (org.hibernate.type.descriptor.sql.BasicBinder:81) - binding parameter [1] as [INTEGER] - [59]
2014-12-19 14:18:29,379 TRACE (org.hibernate.type.descriptor.sql.BasicBinder:81) - binding parameter [2] as [VARCHAR] - [father]
2014-12-19 14:18:29,379 TRACE (org.hibernate.type.descriptor.sql.BasicBinder:81) - binding parameter [3] as [INTEGER] - [210824]
2014-12-19 14:18:29,478 DEBUG (org.hibernate.SQL:109) - 
    insert 
    into
        TEST_ADDRESS
        (ADDRESS_NAME, PERSON_ID, ADDRESS_ID) 
    values
        (?, ?, ?)
2014-12-19 14:18:29,478 TRACE (org.hibernate.type.descriptor.sql.BasicBinder:81) - binding parameter [1] as [VARCHAR] - [lv shun]
2014-12-19 14:18:29,478 TRACE (org.hibernate.type.descriptor.sql.BasicBinder:81) - binding parameter [2] as [INTEGER] - [210824]
2014-12-19 14:18:29,479 TRACE (org.hibernate.type.descriptor.sql.BasicBinder:81) - binding parameter [3] as [INTEGER] - [411]
2014-12-19 14:18:29,575 DEBUG (org.hibernate.SQL:109) - 
    insert 
    into
        TEST_ADDRESS
        (ADDRESS_NAME, PERSON_ID, ADDRESS_ID) 
    values
        (?, ?, ?)
2014-12-19 14:18:29,575 TRACE (org.hibernate.type.descriptor.sql.BasicBinder:81) - binding parameter [1] as [VARCHAR] - [beijing]
2014-12-19 14:18:29,575 TRACE (org.hibernate.type.descriptor.sql.BasicBinder:81) - binding parameter [2] as [INTEGER] - [210824]
2014-12-19 14:18:29,576 TRACE (org.hibernate.type.descriptor.sql.BasicBinder:81) - binding parameter [3] as [INTEGER] - [101]
2014-12-19 14:18:29,672 DEBUG (org.hibernate.SQL:109) - 
    update
        TEST_ADDRESS 
    set
        PERSON_ID=? 
    where
        ADDRESS_ID=?
2014-12-19 14:18:29,672 TRACE (org.hibernate.type.descriptor.sql.BasicBinder:81) - binding parameter [1] as [INTEGER] - [210824]
2014-12-19 14:18:29,673 TRACE (org.hibernate.type.descriptor.sql.BasicBinder:81) - binding parameter [2] as [INTEGER] - [411]
2014-12-19 14:18:29,769 DEBUG (org.hibernate.SQL:109) - 
    update
        TEST_ADDRESS 
    set
        PERSON_ID=? 
    where
        ADDRESS_ID=?
2014-12-19 14:18:29,769 TRACE (org.hibernate.type.descriptor.sql.BasicBinder:81) - binding parameter [1] as [INTEGER] - [210824]
2014-12-19 14:18:29,769 TRACE (org.hibernate.type.descriptor.sql.BasicBinder:81) - binding parameter [2] as [INTEGER] - [101]

在oracle11g上运行会出这种情况，实验环境：oracle11g, jdk1.7,ojdbc6.jar
但在mysql上却按预期般的出错，实验环境：mysql5.6,jdk7