发一个取得函数调用堆栈的函数

代码如下:

js 代码

function getCallStack(){
    var fn, stack;
    if(arguments.length != 2){
        fn = arguments.callee.caller;
        stack = [];
    }else{
        fn = arguments[0];
        stack = arguments[1];
    }
    var fCaller;
    if(fn == null){
        fCaller = "(Top Caller)";
        stack.unshift(fCaller);
        return stack;
    }else{
        var params = /(function\s*([^\(]*)\s*\((.*)\))/.exec(fn.toString());
        if(params != null){
            fCaller = params[1];//"function " + params[1] + "(" + params[2] + ")";
        }else{
            var fnn = fn.toString();
            fnn = fnn.substring(0, fnn.indexOf("\n")==-1 ? 25 : fnn.indexOf("\n"));
            fCaller = "Unknown Caller: " + fnn;
        }
    }
    stack.unshift(fCaller);
    if(fn != null){
        arguments.callee(fn.caller, stack);
    }
    return stack;
}

有个缺点: 如果不是通过function A(){}这种方式定义的函数取不到函数名称

评论

1 楼 ueseu 2007-07-10  

Function.caller is not part of the ECMAScript standard and is not required in conforming implementations. It should not be used