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HttpClient的get和post请求

    博客分类:
  • java
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package com.tw.url.util;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Map;

import org.apache.commons.httpclient.DefaultHttpMethodRetryHandler;
import org.apache.commons.httpclient.Header;
import org.apache.commons.httpclient.HttpClient;
import org.apache.commons.httpclient.HttpException;
import org.apache.commons.httpclient.HttpMethod;
import org.apache.commons.httpclient.HttpStatus;
import org.apache.commons.httpclient.methods.GetMethod;
import org.apache.commons.httpclient.methods.PostMethod;
import org.apache.commons.httpclient.params.HttpMethodParams;

/**
 * <p>
 * HTTP公用类
 *  所需包:Commons-httpclient.jar,commons-codec-1.3.jar
 * 学习参见网址: https://www.ibm.com/developerworks/cn/opensource/os-cn-crawler/
 * </p>
 * 
 * @author tw 2009-07-16
 * 
 */
public class HttpClientUtils {
	
	
	public static void main(String arg[])throws Exception {
		String url = "https://www.99bill.com/webapp/receiveDrawbackAction.do";
		//getDoGetURL2(url,"utf-8");//测试ok
		//getDoGetURL(url,"utf-8");//测试ok
		getDoPostResponseDataByURL(url, null, "utf-8", true); //测试ok
	}

	/**
	 * <p>httpClient的get请求方式</p>
	 * @param url = "https://www.99bill.com/webapp/receiveDrawbackAction.do";
	 * @param charset = ="utf-8";
	 * @return
	 * @throws Exception
	 */
	public static String getDoGetURL(String url, String charset)throws Exception {

		HttpClient client = new HttpClient();
		GetMethod method1 = new GetMethod(url);

		if (null == url || !url.startsWith("http")) {
			throw new Exception("请求地址格式不对");
		}

		// 设置请求的编码方式
		if (null != charset) {
			method1.addRequestHeader("Content-Type",
					"application/x-www-form-urlencoded; charset=" + charset);
		} else {
			method1.addRequestHeader("Content-Type",
					"application/x-www-form-urlencoded; charset=" + "utf-8");
		}
		int statusCode = client.executeMethod(method1);

		if (statusCode != HttpStatus.SC_OK) {// 打印服务器返回的状态
			System.out.println("Method failed: " + method1.getStatusLine());
		}
		// 返回响应消息
		byte[] responseBody = method1.getResponseBodyAsString().getBytes(method1.getResponseCharSet());
		// 在返回响应消息使用编码(utf-8或gb2312)
		String response = new String(responseBody, "utf-8");
		System.out.println("------------------response:"+response);
		// 释放连接
		method1.releaseConnection();
		return response;
	}
	
	
	/**
	 * <p>httpClient的get请求方式2</p>
	 * @param url = "https://www.99bill.com/webapp/receiveDrawbackAction.do";
	 * @param charset = ="utf-8";
	 * @return
	 * @throws Exception
	 */
	public static String getDoGetURL2(String url, String charset)
			throws Exception {
		/*
		 * 使用 GetMethod 来访问一个 URL 对应的网页,实现步骤: 
		 * 1:生成一个 HttpClinet 对象并设置相应的参数。
		 * 2:生成一个 GetMethod 对象并设置响应的参数。 
		 * 3:用 HttpClinet 生成的对象来执行 GetMethod 生成的Get 方法。 
		 * 4:处理响应状态码。 
		 * 5:若响应正常,处理 HTTP 响应内容。 
		 * 6:释放连接。
		 */
		
		/* 1 生成 HttpClinet 对象并设置参数 */
		HttpClient httpClient = new HttpClient();
		// 设置 Http 连接超时为5秒
		httpClient.getHttpConnectionManager().getParams().setConnectionTimeout(5000);

		/* 2 生成 GetMethod 对象并设置参数 */
		GetMethod getMethod = new GetMethod(url);
		// 设置 get 请求超时为 5 秒
		getMethod.getParams().setParameter(HttpMethodParams.SO_TIMEOUT, 5000);
		// 设置请求重试处理,用的是默认的重试处理:请求三次
		getMethod.getParams().setParameter(HttpMethodParams.RETRY_HANDLER,new DefaultHttpMethodRetryHandler());
		
		String response ="";
		/* 3 执行 HTTP GET 请求 */
		try {
			int statusCode = httpClient.executeMethod(getMethod);
			/* 4 判断访问的状态码 */
			if (statusCode != HttpStatus.SC_OK) {
				System.err.println("Method failed: "+ getMethod.getStatusLine());
			}

			/* 5 处理 HTTP 响应内容 */
			// HTTP响应头部信息,这里简单打印
			Header[] headers = getMethod.getResponseHeaders();
			for (Header h : headers)
				System.out.println(h.getName() + "------------ " + h.getValue());
			
			// 读取 HTTP 响应内容,这里简单打印网页内容
			byte[] responseBody = getMethod.getResponseBody();// 读取为字节数组
			response = new String(responseBody, charset);
			System.out.println("----------response:"+response);
			
			// 读取为 InputStream,在网页内容数据量大时候推荐使用
			//InputStream response = getMethod.getResponseBodyAsStream();
			
		} catch (HttpException e) {
			// 发生致命的异常,可能是协议不对或者返回的内容有问题
			System.out.println("Please check your provided http address!");
			e.printStackTrace();
		} catch (IOException e) {
			// 发生网络异常
			e.printStackTrace();
		} finally {
			/* 6 .释放连接 */
			getMethod.releaseConnection();
		}
		return response;
	}
	
    /** 
     * <p>执行一个HTTP POST请求,返回请求响应的HTML</p> 
     * 
     * @param url       请求的URL地址 
     * @param params    请求的查询参数,可以为null 
     * @param charset 	字符集 
     * @param pretty    是否美化 
     * @return 			返回请求响应的HTML 
     */ 
    public static String getDoPostResponseDataByURL(String url,
			Map<String, String> params, String charset, boolean pretty) {
		
    	StringBuffer response = new StringBuffer();
		
		HttpClient client = new HttpClient();
		HttpMethod method = new PostMethod(url);
		
		//设置Http Post数据 
		if (params != null) {
			HttpMethodParams p = new HttpMethodParams();
			for (Map.Entry<String, String> entry : params.entrySet()) {
				p.setParameter(entry.getKey(), entry.getValue());
			}
			method.setParams(p);
		}
		try {
			client.executeMethod(method);
			if (method.getStatusCode() == HttpStatus.SC_OK) {
				//读取为 InputStream,在网页内容数据量大时候推荐使用
				BufferedReader reader = new BufferedReader(
						new InputStreamReader(method.getResponseBodyAsStream(),
								charset));
				String line;
				while ((line = reader.readLine()) != null) {
					if (pretty)
						response.append(line).append(System.getProperty("line.separator"));
					else
						response.append(line);
				}
				reader.close();
			}
		} catch (IOException e) {
			System.out.println("执行HTTP Post请求" + url + "时,发生异常!");
			e.printStackTrace();
		} finally {
			method.releaseConnection();
		}
		System.out.println("--------------------"+response.toString());
		return response.toString();
	} 

	
}
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2 楼 sunnylocus 2010-01-07  
老兄,你是快钱公司的?
1 楼 jxsgy 2009-10-29  
你好,我使用您的代码,post方式发送数据,但是服务端没有接受到

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