Hibenate 1对1关系查询迷惑，请大侠们指点

小弟在项目中使用Hibernate的一对一关系，见.hbm文件如下：
class AcirsUser

<hibernate-mapping>
    <class name="uk.co.quidos.acirs.model.entity.AcirsUser" table="acirs_user" catalog="acirs_v1" lazy="false">
        <id name="userId" type="java.lang.String">
            <column name="user_id" length="32" />
            <generator class="uuid.hex" />
        </id>
        <property name="userName" type="java.lang.String">
            <column name="user_name" length="32" not-null="true" />
        </property>
        <property name="userPwd" type="java.lang.String">
            <column name="user_pwd" length="32" />
        </property>
        <property name="status" type="java.lang.Integer">
            <column name="status" not-null="true" />
        </property>
        
        <one-to-one name="adminInfo" class="uk.co.quidos.acirs.model.entity.AdminInfo" fetch="join"/>
        <one-to-one name="eaInfo" class="uk.co.quidos.acirs.model.entity.EaInfo" fetch="join"/>
        
        <set name="userRoleRels" inverse="true">
            <key>
                <column name="user_id" length="32" not-null="true" />
            </key>
            <one-to-many class="uk.co.quidos.acirs.model.entity.UserRoleRel" />
        </set>
        <set name="preForms" inverse="true">
            <key>
                <column name="user_id" length="32" unique="true" />
            </key>
            <one-to-many class="uk.co.quidos.acirs.model.entity.PreForm" />
        </set>
    </class>
</hibernate-mapping>

class EaInfo：

<hibernate-mapping>
    <class name="uk.co.quidos.acirs.model.entity.EaInfo" table="ea_info" catalog="acirs_v1" lazy="false">
        <id name="userId" type="java.lang.String">
            <column name="user_id" length="32" />
            <generator class="foreign">
            	<param name="property">acirsUser</param>
            </generator>
        </id>
        
        <one-to-one name="acirsUser" class="uk.co.quidos.acirs.model.entity.AcirsUser" constrained="true"/>
        
        <many-to-one name="city" class="uk.co.quidos.acirs.model.entity.City" fetch="select">
            <column name="city_id" length="32" not-null="true" unique="true" />
        </many-to-one>
        <many-to-one name="qualifications" class="uk.co.quidos.acirs.model.entity.Qualifications" fetch="select">
            <column name="qualification_id" length="32" not-null="true" unique="true" />
        </many-to-one>
        <many-to-one name="title" class="uk.co.quidos.acirs.model.entity.Title" fetch="select">
            <column name="title_id" length="32" not-null="true" unique="true" />
        </many-to-one>
        <property name="firstName" type="java.lang.String">
            <column name="first_name" length="64" />
        </property>
        <property name="surName" type="java.lang.String">
            <column name="sur_name" length="64" />
        </property>
        <property name="accreditationScheme" type="java.lang.String">
            <column name="accreditation_scheme" length="128" />
        </property>
        <property name="tel" type="java.lang.String">
            <column name="tel" length="128" />
        </property>
        <property name="email" type="java.lang.String">
            <column name="email" length="128" />
        </property>
        <property name="companyName" type="java.lang.String">
            <column name="company_name" length="128" />
        </property>
        <property name="address1" type="java.lang.String">
            <column name="address1" length="128" />
        </property>
        <property name="address2" type="java.lang.String">
            <column name="address2" length="128" />
        </property>
        <property name="address3" type="java.lang.String">
            <column name="address3" length="128" />
        </property>
        <property name="postCode" type="java.lang.String">
            <column name="post_code" length="64" />
        </property>
        <property name="relatedPartyDisclosure" type="java.lang.String">
            <column name="related_party_disclosure" length="10" />
        </property>
    </class>
</hibernate-mapping>

查询方式2种：
如果使用

select 
acirsUser,eaInfo
from AcirsUser as acirsUser
inner join 
acirsUser.eaInfo as eaInfo

这种方式查询，查询查来的eaInfo项就不为空，而且数据正确

如果使用new map()方式：

select 
new map(acirsUser,eaInfo)
from AcirsUser as acirsUser
inner join 
acirsUser.eaInfo as eaInfo

如果使用new map方式查询出来的eaInfo就为null

比较迷惑，请兄弟姐妹们指点，谢谢 ……