Spring ClassPathXmlApplicationContext疑惑

ApplicationContext.xml文件在使用ClassPathXmlApplicationContext获取Resource对象时,用ClassPathXmlApplicationContext时必须将ApplicationContext.xml放到WEB-INF/classes下面，否则你应该用FileSystemXmlApplicationContext,
然后在web.xml中的<display-name>some   your   modle   info</display-name>后面加上:  
  <context-param>  
     <param-name>contextConfigLocation</param-name>  
     <param-value>classpath:/ApplicationContext.xml</param-value>  
  </context-param> 

Spring .xml相关问题
一个切入点类？  
  用这个吧：  
        BeanFactoryLocator   bfLocator   =   SingletonBeanFactoryLocator.getInstance();  
        BeanFactoryReference   bf   =   bfLocator.useBeanFactory("beanFactory");  
        //   now   use   some   bean   from   factory  
        return   bf.getFactory().getBean(name);  
  －－－－－－－－－－－－－－  
    <beans>  
            <bean   id="beanFactory"   class="org.springframework.context.support.ClassPathXmlApplicationContext">  
            <constructor-arg>  
              <list>  
                <value>dataAccessContext.xml</value>  
                <value>securityContext.xml</value>  
                <value>...</value>  
              </list>  
            </constructor-arg>  
          </bean>  
  </beans>  

如果是WebApplication，用这个也不错。  
  <context-param>  
  <param-name>contextConfigLocation</param-name>  
  <param-value>/WEB-INF/myApplicationContext.xml</param-value>  
  </context-param>  
   
  <servlet>  
  <servlet-name>context</servlet-name>  
  <servlet-class>  
  org.springframework.web.context.ContextLoaderServlet  
  </servlet-class>  
  <load-on-startup>1</load-on-startup>  
  </servlet>