解决return的问题

之前做作业，有一个return的语句，一直在报错，不知道问题出在哪里。觉得不可能有问题，但就是一直显示有错误，怎么样都编译不了，只有把它注释掉，才可以通过编译。但注释return语句后，就不可以达到作业的要求了，很是头疼。

do{
   try{
    stdErr.print("product [name_qty_price]>" );
    stdErr.flush();
   
    product = stdIn.readLine();
     tokenizer = new StringTokenizer(product,"_");
     size = tokenizer.countTokens();
    
    if (size != 3){
     stdOut.println("Invalid input");
    }
    if (size == 3){
     
     name = tokenizer.nextToken();
     quantity = Integer.parseInt(tokenizer.nextToken());
                 price = Double.parseDouble(tokenizer.nextToken());          
    
                if( quantity <= 0 || price < 0){
     stdOut.println("Invalid input");
     }    
    
    }

   }catch (IOException ioe){
    ioe.printStackTrace();
    
    System.exit(0) ;//Terminates the program
    
   }catch(NumberFormatException e)
   {
    stdOut.println(e.toString());
   }
  }while (true);

return new Product(name,quantity, price);

最后想了半天，觉得是return语句的位置有问题，结果把return语句的位置改后，问题就解决了。

do{
   try{
    stdErr.print("product [name_qty_price]>" );
    stdErr.flush();
   
    product = stdIn.readLine();
     tokenizer = new StringTokenizer(product,"_");
     size = tokenizer.countTokens();
    
    if (size != 3){
     stdOut.println("Invalid input");
    }
    if (size == 3){
     
     name = tokenizer.nextToken();
     quantity = Integer.parseInt(tokenizer.nextToken());
                 price = Double.parseDouble(tokenizer.nextToken());         
    
                 if( quantity <= 0 || price < 0){
     stdOut.println("Invalid input");
     }
    
                 else
                return new Product(name,quantity, price);
                
    }
    

   }catch (IOException ioe){
    ioe.printStackTrace();
    
     
    
   }catch(NumberFormatException e)
   {
    stdOut.println(e.toString());
   }
   
  }while (true);

看来还是要在错误中进步啊.........