24点算法的Java低级简易实现

package test;

/**
 * @author QuarterLifeForJava
 */
public class Test {
	
	public static void main(String[] args) {
		int x[] = {8,8,3,3};
		int y[] = new int[x.length];
		for(int a=0;a<4;a++){
			for(int b=0;b<4;b++){
				for(int c=0;c<4;c++){
					for(int d=0;d<4;d++){
						if(a!=b&&b!=c&&c!=d&&d!=a&&a!=c&&b!=d){
							y[0] = x[a];
							y[1] = x[b];
							y[2] = x[c];
							y[3] = x[d];
							for(int i=0;i<4;i++){
								circle(y,i);
							}
						}
					}
				}
			}
		}
		
	}
	
	//边界判断
	public static boolean boundaryJudgment(double result){
		if(result>=23.99999999999999&&result<=24.00000000000001){
			return true;
		}else{
			return false;
		}
	}
	
	//加
	public static double jia(double x,double y){
		return x+y;
	}
	
	//减
	public static double jian(double x,double y){
		return x-y;
	}
	
	//乘
	public static double cheng(double x,double y){
		return x*y;
	}
	
	//除
	public static double chu(double x,double y){
		return x/y;
	}
	
	//循环选择
	public static double change(int num,double x,double y){
		switch(num){
			case 0:
				return jia(x,y);
			case 1:
				return jian(x,y);
			case 2:
				return cheng(x,y);
			case 3:
				return chu(x,y);
		}
		return 0;
	}
	
	//循环计算
	public static void circle(int x[],int choice){
		double mid = 0;
		double y = 0;
		double z = 0;
		for(int i=0;i<4;i++){
			mid = change(i,x[0],x[1]);
			z = mid;
			for(int j=0;j<4;j++){
				mid = z;
				switch(choice){
					case 0:
						mid = change(j,mid,x[2]);
						for(int k=0;k<4;k++){
							y = mid;
							mid = change(k,mid,x[3]);
							if(boundaryJudgment(mid)){
								System.out.println("可算24点");//想输出结果，请自己写个方法，这里略了
								System.exit(0);
							}else{
								mid = y;
							}
						}
						break;
					case 1:
						mid = change(j,mid,x[2]);
						for(int k=0;k<4;k++){
							y = mid;
							mid = change(k,x[3],mid);
							if(boundaryJudgment(mid)){
								System.out.println("可算24点");//想输出结果，请自己写个方法，这里略了
								System.exit(0);
							}else{
								mid = y;
							}
						}
						break;
					case 2:
						mid = change(j,x[2],mid);
						for(int k=0;k<4;k++){
							y = mid;
							mid = change(k,mid,x[3]);
							if(boundaryJudgment(mid)){
								System.out.println("可算24点");//想输出结果，请自己写个方法，这里略了
								System.exit(0);
							}else{
								mid = y;
							}
						}
						break;
					case 3:
						mid = change(j,x[2],mid);
						for(int k=0;k<4;k++){
							y = mid;
							mid = change(k,x[3],mid);
							if(boundaryJudgment(mid)){
								System.out.println("可算24点");//想输出结果，请自己写个方法，这里略了
								System.exit(0);
							}else{
								mid = y;
							}
						}
						break;
				}
			}
		}
	}
}